Ask question

Ask question

All categories

3 years ago

14

4y -7 = 5 -2y +2y +2y add 2y to each side 6y -7 = 5 +7 +7 add 7 to each side y =

2 answers:

Doss [256]3 years ago

8 0

4y-7 = 5-2y+2y+2y
add 2y on both sides
6y-7 = 5+4y
add 7 on both sides
6y-4y=12
2y=12
y=6

Simora [160]3 years ago

3 0

4y - 7 = 5 - 2y

Add 2y to both sides.

6y - 7 = 5

Add 7 to both sides.

6y = 12

Divide both sides by 6

y = 2

You might be interested in

Examine the expression. 17x - 34 Which is an equivalent expression? O 17*(1 + ) O 17x (1-2) O 17+(1-1) O 17*(1 + 2)

mixer [17]

Answer:

17(x-2)

Step-by-step explanation:

Given the expression

17x - 34

We are to factorize it

Get their factors

17x = 17 * x

34 = 17 * 2

Since 17 is common to both factors, hence 17 is the GCF

17x - 34 = 17(x - 2)

Hence the equivalent expression is 17(x-2)

8 0

3 years ago

Help Me???????????????????????????

GarryVolchara [31]

30.56 hope i helped my gurl

5 0

3 years ago

Do the ratios 20/10 and 1/2 form a proportion?

Tems11 [23]

Answer:

Yes . Divide by 10 for 10/20 to get 1/2.

10/10= 1

20/10= 2

10/20= 1/2

6 0

3 years ago

The sum of two terms of gp is 6 and that of first four terms is 15/2.Find the sum of first six terms.

Gnoma [55]

Given:

The sum of two terms of GP is 6 and that of first four terms is $\dfrac{15}{2}.$

To find:

The sum of first six terms.

Solution:

We have,

$S_2=6$

$S_4=\dfrac{15}{2}$

Sum of first n terms of a GP is

$S_n=\dfrac{a(1-r^n)}{1-r}$ ...(i)

Putting n=2, we get

$S_2=\dfrac{a(1-r^2)}{1-r}$

$6=\dfrac{a(1-r)(1+r)}{1-r}$

$6=a(1+r)$ ...(ii)

Putting n=4, we get

$S_4=\dfrac{a(1-r^4)}{1-r}$

$\dfrac{15}{2}=\dfrac{a(1-r^2)(1+r^2)}{1-r}$

$\dfrac{15}{2}=\dfrac{a(1+r)(1-r)(1+r^2)}{1-r}$

$\dfrac{15}{2}=6(1+r^2)$ (Using (ii))

Divide both sides by 6.

$\dfrac{15}{12}=(1+r^2)$

$\dfrac{5}{4}-1=r^2$

$\dfrac{5-4}{4}=r^2$

$\dfrac{1}{4}=r^2$

Taking square root on both sides, we get

$\pm \sqrt{\dfrac{1}{4}}=r$

$\pm \dfrac{1}{2}=r$

$\pm 0.5=r$

Case 1: If r is positive, then using (ii) we get

$6=a(1+0.5)$

$6=a(1.5)$

$\dfrac{6}{1.5}=a$

$4=a$

The sum of first 6 terms is

$S_6=\dfrac{4(1-(0.5)^6)}{(1-0.5)}$

$S_6=\dfrac{4(1-0.015625)}{0.5}$

$S_6=8(0.984375)$

$S_6=7.875$

Case 2: If r is negative, then using (ii) we get

$6=a(1-0.5)$

$6=a(0.5)$

$\dfrac{6}{0.5}=a$

$12=a$

The sum of first 6 terms is

$S_6=\dfrac{12(1-(-0.5)^6)}{(1+0.5)}$

$S_6=\dfrac{12(1-0.015625)}{1.5}$

$S_6=8(0.984375)$

$S_6=7.875$

Therefore, the sum of the first six terms is 7.875.

5 0

3 years ago

Can u help me please

GalinKa [24]

0.15625
$0.15625 \times 64$

5 0

3 years ago

Read 2 more answers