Answer:
Step-by-step explanation:
9.05737
The average of the five consecutive numbers ending with b in discuss when expressed in terms of a is; Choice D; a+3.
<h3>What is the average of five consecutive integers ending with b?</h3>
First, since it was given in the task content that the average of six positive consecutive odd integers starting with a is equal to b, it therefore follows that;
(a+a+2+a+4+a+6+a+8+a+10)/6 = b
6b=6a+30
b=a+5
Also, let the average of the consecutive intergers ending with b be denoted by; x.
(b+b-1+b-2+b-3+b-4)/5 = x
=(5b-10)/5
=b–2
The average, x=b – 2 (where b = a-5)
Ultimately, the value of the required average is; = a+5-2 = a+3.
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Answer:
answer is B
Step-by-step explanation:
I used Desmos to graph the function
Answer:
A.) x-y=2 and x+2y=-2
Step-by-step explanation:
For option A, we have:
x-y=2
x+2y=-2
Subtract the first equation from the second, to get:
2y--y=-2-2
This implies that:
2y+y=-2-2
Simplify to get:
3y=-4
Divide both sides by 3 to get:
We substitute y=-1.3 into the first equation to get:
x--1.3=2
x+1.3=2
x=2-1.3
x=0.7
The solution is (0.7,-1.3), which is approximately (0.7, -1.4)
By inspection, all the other factors have solutions not close to (0.7, -1.4)
Answer:
4%
Step-by-step explanation:
Divide 48 by 1202
48 ÷ 1202
= 0.03993344425956738768718801996672
Round it
0.04 or 4%
