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WITCHER [35]
2 years ago
11

¿Cuál (es) de las siguientes sumas es(son) iguales a 1? (todos los numeros despues de la coma tienen una linea abajo)

Mathematics
1 answer:
Elis [28]2 years ago
8 0

Answer:

1.

Step-by-step explanation:

0.36 + 0.64 = 1

You might be interested in
What is the intersection of y=-x+8
san4es73 [151]
(0,8) on the y axis and (8,0) on the x axis.

Hope this helps if so feel free to give me a brainliest!!!


Have a wonderful day :)
5 0
2 years ago
Read 2 more answers
May I please receive help?
ruslelena [56]

Answer:

so you have to find angles

5 0
2 years ago
Can someone help me pls
rodikova [14]

Answer:

C. 1/3x + 5

Step-by-step explanation:

Plugging in the values for x, we get:

y = 1/3(0) + 5 = 5

y = 1/3(6) + 5 = 7

y = 1/3(12) + 5 = 9

y = 1/3(15) + 5 = 10

I almost broke my neck trying to read this problem. :(

4 0
2 years ago
How many positive integers between 1000 and 9999 inclusive
bekas [8.4K]

Answer:

Step-by-step explanation:

a.

first number is  1000-1+9=1008

9)1000(1

    9

-------

     10

       9

    -----

       10

         9

       ----

         1

       ----

last number is 9999

9| 9999

  ---------

    1111 |0

    --------

9999=1008+(n-1)9

9999-1008=(n-1)9

n-1=8991/9=999

n=999+1=1000

b.

first digit=1000

last digit=9999-1=9998

2 |9999

  ---------

  |4999|1

9998=1000+(n-1)2

(n-1)2=9998-1000=8998

n-1=4499

n=4499=1=5000

c.not sure

d.

total  numbers=9000

9999=1000+(n-1)1

9999-1000=n-1

n=8999+1=9000

numbers divisible by 3=3000

first number=1002

last number=9999

9999=1002+(n-1)3

(n-1)3=9999-1002=8997

n-1=2999

n=2999+1=3000

numbers not divisible by 3=9000-3000=6000

e.

numbers divisible by 5=1800

first number=1000

last number=9995

9995=1000+(n-1)5

(n-1)5=9995-1000=8995

n-1=1799

n=1799+1=1800

numbers divisible by 7=1286

7 | 1000

  ---------

  |  142-6

1000-6+7=1001

7 | 9999

  |---------

    1428-3

9999-3=9996

first digit=1001

last digit=9996

9996=1001+(n-1)7

(n-1)7=9996-1001=8995

n-1=1285

n=1285+1=1286

numbers divisible by 35=257

first digit=1015

35 ) 1000 ( 28

        70

       ----

        300

        280

        ------

           20

           ---

1000-20+35=1015

35)9999(285

     70

    ----

     299

     280

     -----

        199

        175

        ----

          24

         ----

last digit=9999-24=9975

9975=1015+(n-1)35

(n-1)35=9975-1015=8960

n-1=8960/35=256

n=257

reqd. numbers=1800+1286-257=3019

7 0
3 years ago
The length of a rectangle is 5 centimeters less then twice it's width. The perimeter of the rectangle is 26 cm. What are the dim
Sedaia [141]

Answer:

The dimensions of the rectangle are length = 7cm and width = 6cm.

Step-by-step explanation:

In order to solve for the dimensions, you will need to set up two equations in order to solve for the missing variable.  Given the information that the length is 5 cm less then twice it's width, using 'L' for length and 'w' for width we get the following equation:  L = 2w - 5.  Perimeter is the sum of all the sides, or in the case of a rectangle P = 2w + 2L.  We can then use our expression for 'L' in our perimeter formula:  26 = 2w + 2(2w - 5).  First, using the distributive property we get: 26 = 2w + 4w - 10.  Next, we combine like terms:  26 = 6w - 10.  Then, we use inverse operations to isolate the variable:  26 + 10 = 6w - 10 + 10 to get 36 = 6w, divide both sides by 6 to get w = 6.  Lastly, plug in the value of 'w' to 'L':  L = 2(6) - 5 or L = 7.

3 0
3 years ago
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