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murzikaleks [220]
3 years ago
9

Please help urgent all info is in screenshot

Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
3 0

<em>IT</em><em> </em><em>IS</em><em> </em><em>A</em><em> </em><em>DIRECT</em><em> </em><em>VARIATION</em><em>.</em><em>.</em><em>.</em><em>BECAUSE</em><em> </em><em>WHEN</em><em> </em><em>X</em><em> </em><em>COMPONENT</em><em> </em><em> </em><em>IS</em><em> </em><em>INCREASED</em><em> </em><em>THE</em><em>N</em><em> </em><em>Y</em><em> </em><em>COMPONENT</em><em> </em><em>ATE</em><em> </em><em>ALSO</em><em> </em><em>INCREASING</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>

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Mark and his friends order two pizzas of the same size .•The first pizza is cut into 6 slices of equal size .•The second pizza i
nydimaria [60]

Mark is correct because taking a slice from each pizza would be 3/6 or 1/2 of the pizza but taking two slices of the first pizza, Mark wouldn't get as much because that is the same as 2/6 or 1/3 of the pizza. 1/2 > 1/3 therefore Marks conclusion is correct.

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3 years ago
Jerome's credit card has an APR of 18%, calculated on the previous monthly
Aleonysh [2.5K]

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Step-by-step explanation:

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3 years ago
What is the simplified form of the quantity 12 z–squared minus 7z minus 12 over the quantity 3 z–squared plus 2z minus 8
loris [4]
The most important part of this problem is reading the problem carefully and then solving it. Most of the required information's are already given in the question. Let us now focus on the problem in hand.

(12z^2 - 7z -12)/(3z^2 + 2z - 8) = [12z^2 - 16z + 9z - 12]/[3z^2 + 6z - 4z - 8]
                                                  = [4z(3z - 4) + 3(3z - 4)/[(3z(z + 2) -4(z + 2)]
                                                  = [(4z + 3)(3z - 4)]/(z + 2) (3z - 4)]
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The above deduction is the simplified form. I hope that this is the answer that has come to your desired help.
5 0
3 years ago
Find the exact value of the trigonometric expression given that sin(u) = -(3/5),
GuDViN [60]

Recall that

\cot(u+v)=\dfrac{\cos(u+v)}{\sin(u+v)}=\dfrac{\cos u\cos v-\sin u\sin v}{\sin u\cos v+\cos u\sin v}=\dfrac{\cot u\cot v-1}{\cot v+\cot u}

Also, recall that for all \theta,

\cos^2\theta+\sin^2\theta=1

With \frac{3\pi}2, we can expect \cos u>0, and with 0, \sin v>0. So from the above identity it follows that

\cos u=\sqrt{1-\sin^2u}=\dfrac45\implies\cot u=\dfrac{\cos u}{\sin u}=-\dfrac43

and

\sin v=\sqrt{1-\cos^2v}=\dfrac8{17}\implies\cot v=\dfrac{\cos v}{\sin v}=\dfrac{15}8

and so

\cot(u+v)=\dfrac{-\frac43\frac{15}8-1}{\frac{15}8-\frac43}=\boxed{-\dfrac{84}{13}}

6 0
3 years ago
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