1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Y_Kistochka [10]
3 years ago
12

Evaluate the expression when a= -3 and C = 6 8c - a​

Mathematics
1 answer:
DanielleElmas [232]3 years ago
4 0
51
hope this helps!!
You might be interested in
Simplify the expression 2(10)+2(×-4)
Gnoma [55]

Answer:

Step-by-step explanation:

22x-88

20+2(x-4)

22x-88

6 0
3 years ago
Simplify 150−55t to get the correct answer
morpeh [17]
Well it’s but that’s d yup nope no I’m kidding I’m not sure but I just hate it I hate you so I just hate it lol I love love y’all love bye love y’all love love y’all are y’all ok ok well yeah ok ok well I just hate to bother pls

4 0
3 years ago
Read 2 more answers
Order the following radicals from the least to greatest without using a calculator. show your reasoning
Shalnov [3]

Answer:

2*sqrt6 = 2*apprx2 = 4

5*sqrt10 = 5*3.1 = 15.5

4*sqrt2 = 4*1.4 = 6.4

3*sqrt3  = 3*1.7 = 5.1

4, 5.1, 6.4, 15.5 or... 2sqrt6, 3sqrt3, 4sqrt2, 5sqrt10

 

​

7 0
3 years ago
The polygons are similar. The area of one polygon is given. Find the area of the other polygon.
kap26 [50]

Answer:

90 cm²

Step-by-step explanation:

Given that both triangles are similar, it follows that the ratio of their area equals the square of their corresponding sides.

Let the area of the other triangle be x. Therefore:

\frac{10}{x} = \frac{4^2}{12^2}

\frac{10}{x} = \frac{16}{144}

Cross multiply

10*144 = 16*x

1440 = 16x

Divide both sides by 16

90 = x

Area of the other polygon = 90 cm²

4 0
3 years ago
Which congruence postulate or theorem is stated below?
a_sh-v [17]

The congruence postulate or theorem that is stated is the: C. AAS congruence theorem.

<h3>What are Congruent Triangles?</h3>

Triangles that are referred to as congruent triangles are triangles that have corresponding congruent sides and corresponding congruent angles.

<h3>What is the Angle-angle-side Congruence Theorem (AAS)?</h3>

According to the angle-angle-side congruence theorem (AAS) two triangles are congruent if two angles and a non-included side of one triangle are congruent to two corresponding angles and a non-included side of the other are congruent to each other.

For example, in triangles GUM and RED given in the image attached below, we have the following:

∠G ≅ ∠R [a pair of congruent angles]

∠M ≅ ∠D [a pair of congruent angles]

GU ≅ RD [a pair of non-included congruent side]

Thus, both triangles are congruent by the AAS, which is the congruence theorem that is stated above.

The answer is: C. AAS.

Learn more about the AAS congruence theorem on:

brainly.com/question/3168048

#SPJ1

6 0
2 years ago
Other questions:
  • Which of the following represents 3π, rounded to the nearest tenths?
    14·1 answer
  • A family of 4 is buying cell phones. Each phone costs a dollars if the family buys the super plan which costs
    9·1 answer
  • Each section of a running trail is 3/4 miles. The trail has 3 sections.
    7·2 answers
  • Shawn has 186 feet of fencing and plans to make a pig pen that is 15 feet wide. How long will the pig pen be? Remember the formu
    13·1 answer
  • The Golden family is planning to buy a house that sells for $125,000. They want to put 20% as a down payment. How much would the
    12·1 answer
  • Please help please???????​
    15·1 answer
  • Which equation represents a line which is perpendicular to the line y= –1/8x + 8
    14·1 answer
  • Consider the sequence of numbers: , , 1StartFraction 3 Over 8 EndFraction, StartFraction 3 Over 4 EndFraction, 1 and StartFracti
    14·2 answers
  • What is x-2+=6 because my teacher say that it's not hard and i look hard
    7·2 answers
  • Which of the following is an example of a theorem?
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!