Which point does NOT lie on the graph of the line x + 2y = 9?

Help me with this too!

Tasya [4]

X = 17
5 = x - 12
12 + 5 = x
17 = x

4 0

3 years ago

Negative 2X minus 2X equals 10+ 6X

Kay [80]

The corrrct answer is x= -1

8 0

3 years ago

Read 2 more answers

IQ scores are normally normally distributed with a mean of 100 and center deviation of 15 if one person is randomly selected wha

Arlecino [84]

Answer:

22.86% probability that the persons IQ is between 110 and 130

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 100, \sigma = 15$

If one person is randomly selected what is the probability that the persons IQ is between 110 and 130

This is the pvalue of Z when X = 130 subtracted by the pvalue of Z when X = 110.

X = 130

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{130 - 100}{15}$

$Z = 2$

$Z = 2$ has a pvalue of 0.9772

X = 110

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{110 - 100}{15}$

$Z = 0.67$

$Z = 0.67$ has a pvalue of 0.7486

0.9772 - 0.7486 = 0.2286

22.86% probability that the persons IQ is between 110 and 130

6 0

3 years ago

ALGREBRA - 4 PARTS

xenn [34]

Answer:

Estimate of population 0.61

(b) Margin of error = 0.07 The real population interval estimation is ± 7%.

c). Margin of error = 0.15

d) The real population's interval estimation is ± 15%

e). Yes, the action argument of the group is based on a half-range estimation of the true population. The reason that 62% ± 15% = 47%, or 77%, while 47% is similar to 45%, as the Collective action group states.

6 0

3 years ago

A counselor records the number of disagreements (per session) among couples during group counseling sessions. If the number of d

Shalnov [3]

Answer:

$P(X>4)=P(\frac{X-\mu}{\sigma}>\frac{4-\mu}{\sigma})=P(Z>\frac{4-4.4}{0.4})=P(z>-1)$

And we can find this probability with the complement rule:

$P(z>-1)=1-P(z$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the disagreements of a population, and for this case we know the distribution for X is given by:

$X \sim N(4.4,0.4)$