Answer:
Discriminant: -4
No real solutions
Step-by-step explanation:
You might remember this long, seemingly very hairy thing called the <em>quadratic formula</em> from earlier in algebra:
The <em>discriminant</em> of a quadratic equation of the form is that bit under the square root: . What does the discriminant tell us? Since we're taking its square root, we know that is only real for non-negative values of . If , we have two real roots, one for and one for . If , the function has a rational root, since the formula becomes
In your case, we have the equation ; here, , , and , so our discriminant is . Since we'd have a negative under our square root in the quadratic formula, we have <em>no real solutions</em>.
Let n be the first even integer, and n+2 will be the second even integer. (Why? Think 2 and 4, 2+2=4. This is the case for every consecutive even integers).
n + 3(n+2) = 54
n + 3n + 6 = 54
4n = 48
n = 12, n+2 = 14
I thought it said 21 pilots at first
50 tickets for the students
20 for the adults tickets to make profit