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Alexeev081 [22]
3 years ago
13

Mr. Berger is building a sandbox for his children. The sandbox is in the shape of a right rectangular prism. The area of the bas

e of the sandbox is 49.2 square feet, and it will have a height of 2.25 feet. Mr. Berger plans to fill the sandbox half full of sand.
What is the volume of sand he will need to fill half of the sandbox?

A. 21.87 FEET CUBED

B. 55.35 FEET CUBED

C. 125 FEET CUBED

D. 110.7 FEET CUBED
Mathematics
1 answer:
Kazeer [188]3 years ago
5 0

Answer:

110.7 feet cubed

Step-by-step explanation:

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What is the area of a circle, rounded to the nearest tenth, with a<br> diameter of 12 centimeters?
inessss [21]

Answer:

113

Step-by-step explanation:

area of a circle is 3.14*r^2

r=d/2 r=6

3.14*36=113

3 0
3 years ago
During a bike challenge riders have to collect serious colored ribbons each 1/2 mile they collect a red ribbon each three 1/8 mi
hjlf

You need to give a little more detail. I don't understand what you are asking.

3 0
4 years ago
Please this is due tonight!!! Express given logarithm in terms of a, b and c.
KATRIN_1 [288]

\textit{Logarithm Change of Base Rule} \\\\ \log_a b\implies \cfrac{\log_c b}{\log_c a}\qquad \qquad c= \begin{array}{llll} \textit{common base for }\\ \textit{numerator and}\\ denominator \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \log_5(18)\implies \cfrac{\log(18)}{\log(5)}\implies \cfrac{\log(2\cdot 3\cdot 3)}{\log(5)}\implies \cfrac{\log(2)+\log(3)+\log(3)}{\log(5)}

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8 0
3 years ago
12.) Write y = 1/6 x + 7 in standard form using integers.
Trava [24]

Option A

-x + 6y = 42 is the standard form

<u>Solution:</u>

Given that we have to write y = \frac{1}{6}x+7 in standard form

The standard form of an equation is Ax + By = C

In this kind of equation, x and y are variables and A, B, and C are integers

Given equation is:

y = \frac{1}{6}x+7

Let us convert the above equation into standard form

y = \frac{x}{6} + 7

y = \frac{x}{6} + \frac{7}{1}

Make the denominator same in R.H.S

y = \frac{x}{6} + \frac{7 \times 6}{1 \times 7}

Solve the above equation

y = \frac{x}{6} + \frac{42}{6}

y = \frac{x+42}{6}

Move 6 from R.H.S to L.H.S

6y = x + 42

Bring all the terms to one side, leaving only constant on R.H.S

-x + 6y = 42

The above equation is of form Ax + By = C

Thus option A is correct

3 0
3 years ago
Given: ΔАВС, m∠ACB = 90°
dalvyx [7]
1. Length of CD
Considering Triangle CDB
Angle DCB = 30
Using trigonometric ratio 
Cos θ = adjacent/hypotenuse
Cos 30 = CD/CB
Cos 30 = CD/6
CD = 6(Cos 30)
      = 5.196 cm

2. The area of triangle ABC
area of Δ ABC = ares of Δ ACD + Area of DCB
Area of Δ DCB
= 1/2 × 3× 5.195
 = 7.79 cm²
length of AD
  Tan 60 = AD/5.196
AD= 8.999
      ≈ 9 cm
Area of of ADC
= 1/2 × 9 × 5.196 
  = 23.382 cm²
Therefore area of Δ ABC
    = 23.382 cm² + 7.79 cm²
     = 31.172 cm² 
7 0
3 years ago
Read 2 more answers
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