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saw5 [17]
3 years ago
7

A bowl contains 7 pennies, 9 nickels, and 4 dimes. Elyse removes one coin at random from the bowl and does not replace it. She t

hen removes a second coin at random. What is the probability that both will be dimes?
Mathematics
1 answer:
Vlad [161]3 years ago
6 0

Answer:

The probability is 3/95

Step-by-step explanation:

Okay this is a probability without replacement question.

Firstly we calculate the total number of coins = 7 + 9 + 4 = 20 coins

The probability that the first coin will be a dimes = number of dimes/total number of coins = 4/20 = 1/5

Now she removes a coin without replacement, if it was a dime, total number of coins becomes 19 and the total number of dimes becomes 3; Thus the probability of the second coins being a dimes = 3/19

Thus, the probability of both coins being dimes = probability of first coin being dimes * probability of second coins being dimes

= 1/5 * 3/19 = 3/95

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Answer:

x = -14

Step-by-step explanation:

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3 years ago
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Answer:

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3 years ago
What is 1 and 3/4 divided by 4/5​
icang [17]

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Does 3 (x-1) = 2x + 9 have one solution, no solution, or infinite solutions?
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