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saw5 [17]
3 years ago
7

A bowl contains 7 pennies, 9 nickels, and 4 dimes. Elyse removes one coin at random from the bowl and does not replace it. She t

hen removes a second coin at random. What is the probability that both will be dimes?
Mathematics
1 answer:
Vlad [161]3 years ago
6 0

Answer:

The probability is 3/95

Step-by-step explanation:

Okay this is a probability without replacement question.

Firstly we calculate the total number of coins = 7 + 9 + 4 = 20 coins

The probability that the first coin will be a dimes = number of dimes/total number of coins = 4/20 = 1/5

Now she removes a coin without replacement, if it was a dime, total number of coins becomes 19 and the total number of dimes becomes 3; Thus the probability of the second coins being a dimes = 3/19

Thus, the probability of both coins being dimes = probability of first coin being dimes * probability of second coins being dimes

= 1/5 * 3/19 = 3/95

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Y equals the quotient of the quantity x squared plus 4 times x and the quantity x cubed minus 5.
koban [17]

Given:

Consider the completer question is "Find the derivative \dfrac{dy}{dx} for y=\dfrac{x^2-4x}{x^3-5}."

To find:

The derivative \dfrac{dy}{dx}.

Solution:

Chain rule: \dfrac{d}{dx}f(g(x))=f'(g(x))\cdot g'(x)

Quotient rule: \dfrac{d}{dx}\dfrac{f(x)}{g(x)}=\dfrac{g(x)f'(x)-f(x)g'(x)}{[g(x)]^2}

We have,

y=\dfrac{x^2-4x}{x^3-5}

Differentiate with respect to x.

\dfrac{dy}{dx}=\dfrac{d}{dx}\left(\dfrac{x^2-4x}{x^3-5}\right)

Using chain rule and quotient rule, we get

\dfrac{dy}{dx}=\dfrac{(x^3-5)\dfrac{d}{dx}(x^2-4x)-(x^2-4x)\dfrac{d}{dx}(x^3-5)}{(x^3-5)^2}

\dfrac{dy}{dx}=\dfrac{(x^3-5)(2x-4)-(x^2-4x)(3x^2)}{(x^3-5)^2}

\dfrac{dy}{dx}=\dfrac{2x^4-4x^3-10x+20-3x^4+12x^3}{(x^3-5)^2}

\dfrac{dy}{dx}=\dfrac{-x^4+8x^3-10x+20}{(x^3-5)^2}

Therefore, the required answer is \dfrac{dy}{dx}=\dfrac{-x^4+8x^3-10x+20}{(x^3-5)^2}.

4 0
3 years ago
What is the slope for (5,7) (-4,-2)
Wewaii [24]

Answer:

Slope = 1

Step-by-step explanation:

7 0
3 years ago
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The diagram shows a circle inside a square 16cm Work out the area of the circle
vesna_86 [32]

i can help if you have the picture

5 0
3 years ago
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An exterior angle of an isosceles triangle has measure 130°. Find two possible sets of measures for the angles of the triangle.
frozen [14]
(1) it can be both exterior of vertex or base. 180-130=50°
vertex is 50°:     base=(180-50)/2=65°
base is 50°:       vertex= 180-2*50=80°

vertex 50 base 65; vertex 80, base 50

(2)base=180-130=50°
vertex=180-2*50=80°

base 50 vertex 80
5 0
3 years ago
In triangle $ABC,$ point $D$ is on $\overline{AC}$ such that $AD = 3CD = 12$. If $\angle ABC = \angle BDA = 90^\circ$, then what
Neporo4naja [7]

Answer:

BD=4\sqrt{3}\ units

Step-by-step explanation:

we know that

AD=12\ units

3CD=12 ----> CD=4\ units

see the attached figure to better understand the problem

Triangles ABD and BCD are similar by AA Similarity Theorem

Remember that

If two figures are similar, then the ratio of its corresponding sides is proportional

so

\frac{BD}{AD}=\frac{CD}{BD}

substitute the given values

\frac{BD}{12}=\frac{4}{BD}

BD^2=48

BD=\sqrt{48}\ units

simplify

BD=4\sqrt{3}\ units

8 0
3 years ago
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