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Setler [38]
3 years ago
12

Write an equation that describes the function. Pls help I will give brainliest!!! ​

Mathematics
1 answer:
andriy [413]3 years ago
5 0

Answer:

y=x+7

Step-by-step explanation:

just plug it in on a coordinate plane and you should get your answer I'll attach a screenshot

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(8 points)
Harman [31]

Answer:

b. period boss queen

y is an integer needed to be graphed on a map

Step-by-step explanation:

5 0
2 years ago
A grocery store sells a bag of 4 oranges for $2.84. If Arianna spent $3.55 on oranges,
zhannawk [14.2K]
$4/3=$1.33 per pound.
$9/8 = $1.13 per pound.
The second one is cheaper.
3 0
3 years ago
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Solve the equation 5x + 7y = 35 for y.
erastovalidia [21]

Answer:

D. y = -5/7x + 5

Step-by-step explanation:

5x + 7y = 35

-5x          -5x

7y =  35 - 5x

/7      /7    /7

y = 35/7 - 5/7 x

y = 5 - 5/7x

4 0
4 years ago
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What is an equation for a sine curve with amplitude 2, and period 4pi radians ?
Nezavi [6.7K]
<span>1. a sine curve with amplitude 2, and period 4pi radians
</span>
the general equation of the sine curve ⇒⇒ y = a sin (nθ)
where: a is the amplitude  and  n = 2π/perid
∵ <span>amplitude 2, and period 4pi radians
</span>
∴ y = 2 sin (θ/2)

The correct answer is option D. y = 2 sin (θ/2)
===========================================

<span>2.The period and amplitude of the function ⇒⇒ y = 5 cos 2θ
</span>
<span>comparing with y = a cos nθ
</span>
where : a is the amplitude  and  n = 2π/period
<span>amplitude = 5  , period = 2π/n = 2π/2 = π
</span>

The correct answer is option B. Period: pi radians: Amplitude:5

============================================================
3. tan (2π/3) = tan 120° = -√3 
120° lie in the second quadrant and its reference angle = 180° - 120° = 60°
tan function in the second quadrant is negative
∴ tan 120° = - tan 60 = -√3

The correct answer is C. -sqrt3

=====================================================
4. <span>Tan 5π/6 = tan 150° = -(√3)/3
</span>
150° lies in the second quadrant and its reference angle = 180° - 150° = 30°
tan function in the second quadrant is negative
∴ tan 150° = - tan 30 = -(√3)/3

The correct answer is <span>B.-sqrt3/3</span>
8 0
3 years ago
PLEASE HELP 100 points + b.
VLD [36.1K]

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8 0
3 years ago
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