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lina2011 [118]
3 years ago
15

Cheddar cheese costs 7.50 for 1 kg Marie buys 200 grams of cheddar cheese how much does she pay

Mathematics
2 answers:
Varvara68 [4.7K]3 years ago
8 0
Marie would pay $1.50 because 200 grams is .2 Kg and you would multiply 7.50 by .2 and you'd get your answer
sergeinik [125]3 years ago
6 0

The <em><u>correct answer</u></em> is:

$1.50.

Explanation:

1 kg = 1000 g. We can set up a proportion to solve this:

7.50/1000g = x/200g

Cross multiply:

200(7.50) = x(1000)

1500 = 1000x

Divide both sides by 1000:

1500/1000 = 1000x/1000

1.50 = x

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Calculate the limit of the function with L'Hospital rule​
mr_godi [17]

Answer:

L=24

Step-by-step explanation:

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Rule is that if \lim_{x \to a} \frac{f(x)}{g(x)} takes \frac{0}{0} or \frac{\infty}{\infty} form, then,

\lim_{x \to a} \frac{f(x)}{g(x)}= \lim_{x \to a} \frac{f'(x)}{g'(x)}

where f'(x)=\frac{df(x)}{dx} and g'(x)=\frac{dg(x)}{dx}

Now coming to the problem,

L= \lim_{x \to \frac{\pi}{6} } \frac{cot^{3}x-3cotx}{cos(x+\frac{\pi}{3} )}

Here f(x)=cot^{3}x-3cotx and g(x)=cos(x+\frac{\pi}{3} )

Substituting x=\frac{\pi}{6} in f(x) and g(x),

f(\frac{\pi}{6})=cot^{3}\frac{\pi}{6}-3cot\frac{\pi}{6}\\=3\sqrt{3}-3\sqrt{3}\\ =0

g(\frac{\pi}{6})=cos(\frac{\pi}{6}+\frac{\pi}{3})\\=cos\frac{\pi}{2}\\=0

Since L takes the form \frac{0}{0}, using l'hopital's rule

L= \lim_{x \to \frac{\pi}{6}} \frac{cot^{3}x-3cotx}{cos(x+\frac{\pi}{3})}= \lim_{x \to \frac{\pi}{6}} \frac{3cot^{2}x(-cosec^{2}x)-3(-cosec^{2}x)}{-sin(x+\frac{\pi}{3})}

now substituting x=\frac{\pi}{6} ,

L= \lim_{x \to \frac{\pi}{6}} \frac{3cot^{2}\frac{\pi}{6}(-cosec^{2}\frac{\pi}{6})-3(-cosec^{2}\frac{\pi}{6})}{-sin(\frac{\pi}{6}+\frac{\pi}{3})}\\=\frac{3*3^{2}(-2^{2})+3(2^{2})}{-1}\\=24

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