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AVprozaik [17]
3 years ago
10

This is the last questionn help

Mathematics
1 answer:
makkiz [27]3 years ago
7 0

Answer:

C

Step-by-step explanation:

That's the answer....

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If P(E) = 0.32, then what are the odds against E?
steposvetlana [31]

Answer:

0.68 : 0.32

Step-by-step explanation:

the probability of all the outcomes of an event is always 1 .

if P(E) = 0.32,

P(E') = 1 - 0.32

= 0.68

N.B that P(E') is the same as P( not E ).

since your answer should be given in the ratio form, as the odds against E ( probability not E : probability E),

P(E') : P(E)

0.68 : 0.32

hope this helps you!

-s.

7 0
2 years ago
Find the solution of the given initial value problem:<br><br> y''- y = 0, y(0) = 2, y'(0) = -1/2
igor_vitrenko [27]

Answer:  The required solution of the given IVP is

y(x)=\dfrac{3}{4}e^x+\dfrac{5}{4}e^{-x}.

Step-by-step explanation:  We are given to find the solution of the following initial value problem :

y^{\prime\prime}-y=0,~~~y(0)=2,~~y^\prime(0)=-\dfrac{1}{2}.

Let y=e^{mx} be an auxiliary solution of the given differential equation.

Then, we have

y^\prime=me^{mx},~~~~~y^{\prime\prime}=m^2e^{mx}.

Substituting these values in the given differential equation, we have

m^2e^{mx}-e^{mx}=0\\\\\Rightarrow (m^2-1)e^{mx}=0\\\\\Rightarrow m^2-1=0~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mx}\neq0]\\\\\Rightarrow m^2=1\\\\\Rightarrow m=\pm1.

So, the general solution of the given equation is

y(x)=Ae^x+Be^{-x}, where A and B are constants.

This gives, after differentiating with respect to x that

y^\prime(x)=Ae^x-Be^{-x}.

The given conditions implies that

y(0)=2\\\\\Rightarrow A+B=2~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

and

y^\prime(0)=-\dfrac{1}{2}\\\\\\\Rightarrow A-B=-\dfrac{1}{2}~~~~~~~~~~~~~~~~~~~~~~~~(ii)

Adding equations (i) and (ii), we get

2A=2-\dfrac{1}{2}\\\\\\\Rightarrow 2A=\dfrac{3}{2}\\\\\\\Rightarrow A=\dfrac{3}{4}.

From equation (i), we get

\dfrac{3}{4}+B=2\\\\\\\Rightarrow B=2-\dfrac{3}{4}\\\\\\\Rightarrow B=\dfrac{5}{4}.

Substituting the values of A and B in the general solution, we get

y(x)=\dfrac{3}{4}e^x+\dfrac{5}{4}e^{-x}.

Thus, the required solution of the given IVP is

y(x)=\dfrac{3}{4}e^x+\dfrac{5}{4}e^{-x}.

4 0
3 years ago
What is 14/10 in percent form?
Lilit [14]
Get the value of the decimal:
\frac{14}{10}=1.40

Remember that percentages are simply the value of a decimal multiplied by 100. (From the Latin, "per centus", meaning "per 100")

therefore:
1.40(100)=140percent
4 0
3 years ago
Read 2 more answers
( -3/4 + 4/3) + i =0 Show your work. (Please help)
Effectus [21]

Answer:

i = -7/12

Step-by-step explanation:

(-3/4 + 4/3) + i = 0

(-9/12 + 16/12) + i = 0

7/12 + i = 0

i = -7/12

6 0
2 years ago
Read 2 more answers
N is the midpoint of AC; AN = 4x - 7 and NC = 5x - 15<br> Find NC=
coldgirl [10]

Answer:

A____N____C

AN= NC

4x-7=5x-15

5x-4x= 15-7

x= 8

NC = 5x-15=5(8) – 15 = 40 – 15 = 25

I hope I helped you^_^

4 0
2 years ago
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