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2 years ago

11

GUYS HELP ME.. plEASEEEEE

1 answer:

Nataly_w [17]2 years ago

5 0

Answer:

19000 Pa

Step-by-step explanation:

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I NEED HELP ASAP!!!!!!

natita [175]

Answer:

$3\sqrt{7}$

Step-by-step explanation:

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2 years ago

According to cbs money watch, the average monthly household cellular phone bill is $100. suppose monthly household cell phone bi

iren2701 [21]

<span>The probability that a randomly selected monthly cell phone bill is more than $127 is given by

$P(X\ \textgreater \ 127)=1-P(X\ \textless \ 127) \\ \\ =1-P\left(z\ \textless \ \frac{127-100}{11.35} \right)=1-P(z\ \textless \ 2.38) \\ \\ =1-0.99132=0.00868$ </span>

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2 years ago

Match the equations of the lines with their graphs.

nika2105 [10]

Answer:1. y = 2x - 3

2. y= 2x + 3

3. y = -2x + 3

4. y = -2x - 3

Step-by-step explanation:

5 0

2 years ago

Please solve 5 f <br> (Trigonometric Equations)<br> #salute u if u solved it

Zanzabum

Answer:

$\beta=45\degree\:\:or\:\:\beta=135\degree$

Step-by-step explanation:

We want to solve $\tan \beta \sec \beta=\sqrt{2}$ , where $0\le \beta \le360\degree$ .

We rewrite in terms of sine and cosine.

$\frac{\sin \beta}{\cos \beta} \cdot \frac{1}{\cos \beta} =\sqrt{2}$

$\frac{\sin \beta}{\cos^2\beta}=\sqrt{2}$

Use the Pythagorean identity: $\cos^2\beta=1-\sin^2\beta$ .

$\frac{\sin \beta}{1-\sin^2\beta}=\sqrt{2}$

$\implies \sin \beta=\sqrt{2}(1-\sin^2\beta)$

$\implies \sin \beta=\sqrt{2}-\sqrt{2}\sin^2\beta$

$\implies \sqrt{2}\sin^2\beta+\sin \beta- \sqrt{2}=0$

This is a quadratic equation in $\sin \beta$ .

By the quadratic formula, we have:

$\sin \beta=\frac{-1\pm \sqrt{1^2-4(\sqrt{2})(-\sqrt{2} ) } }{2\cdot \sqrt{2} }$

$\sin \beta=\frac{-1\pm \sqrt{1^2+4(2) } }{2\cdot \sqrt{2} }$

$\sin \beta=\frac{-1\pm \sqrt{9} }{2\cdot \sqrt{2} }$

$\sin \beta=\frac{-1\pm3}{2\cdot \sqrt{2} }$

$\sin \beta=\frac{2}{2\cdot \sqrt{2} }$ or $\sin \beta=\frac{-4}{2\cdot \sqrt{2} }$

$\sin \beta=\frac{1}{\sqrt{2} }$ or $\sin \beta=-\frac{2}{\sqrt{2} }$

$\sin \beta=\frac{\sqrt{2}}{2}$ or $\sin \beta=-\sqrt{2}$

When $\sin \beta=\frac{\sqrt{2}}{2}$ , $\beta=\sin ^{-1}(\frac{\sqrt{2} }{2} )$

$\implies \beta=45\degree\:\:or\:\:\beta=135\degree$ on the interval $0\le \beta \le360\degree$ .

When $\sin \beta=-\sqrt{2}$ , $\beta$ is not defined because $-1\le \sin \beta \le1$

4 0

2 years ago

NEED ANSWER ASAP BRIANLIEST TO GIVE A house increases in price by 3% each year. If the house starts at £180,000, how much is it

kow [346]

Answer:

£196,690.86 or £196,691

4 0

2 years ago