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3 years ago

What is the minimum number of triangles needed to construct a hexagon?

Mathematics

2 answers:

Sholpan [36]3 years ago

8 0

Answer:

Step-by-step explanation:

torisob [31]3 years ago

4 0

Answer:

a polygon has 5 or more sides and is made of 4 triangles your asking for the name of it which is confusing because then you list a 8,6,7 and 4 sided shapes can you explain that? so it could be A,B, or C but only one you can make in to 4 triangle so i would go with B

Step-by-step explanation:

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The perimeter of a rectangular field is 320320 yd. the length is 2020 yd longer than the width. find the dimensions.

hichkok12 [17]

The sum of length and width is half the perimeter, 160 yd. The length is the average of the sum and difference of dimensions:
.. (160 +20)/2 = 90
Then the width is 160 -90 = 70

The rectangular field is 70 yd by 90 yd.

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3 years ago

What is the period of `y = 1+ tan((1)/(2)x)`?

jonny [76]

2π is the period of `y = 1+ tan((1)/(2)x)`

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3 years ago

A candy company can make 350 pounds of chocolate and 6 hours how much can they make in 10 hours

Andrew [12]

350 ÷ 6 = 58.33

58.33 pounds of chocolate per hour

58.33 × 10 = 583.3

583.33 pounds of chocolate in 10 hours

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3 years ago

Read 2 more answers

These are the fees for sending a package by Media Mail: $2.41 for the first pound $0.41 per additional pound for the next six po

den301095 [7]

2.41+6(0.41)+(lb-7)0.39=7.99

2.41+2.46-2.73+0.39lb=7.99

0.39lb=5.85

lb=15

The package of books weights 15 pounds...

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4 years ago

Which of the following equations represents the perpendicular bisector of WX graphed below?

kotykmax [81]

The coordinates of the 2 given points are W(-5, 2), and X(5, -4).

First, we find the midpoint M using the midpoint formula:

$\displaystyle{ M_{WX}= (\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2} )= (\frac{-5+5}{2}, \frac{2+(-4)}{2} )=(0, -1).$

Nex, we find the slope of the line containing M, perpendicular to WX. We know that if m and n are the slopes of 2 parallel lines, then mn=-1.

The slope of WX is $\displaystyle{ m= \frac{y_2-y_1}{x_2-x_1}= \frac{2-(-4)}{-5-5}= \frac{6}{-10}= -\frac{3}{5}$ .

Thus, the slope n of the perpendicular line is $\displaystyle{ \frac{5}{3}$ .

The equation of the line with slope $\displaystyle{ n= \frac{5}{3}$ containing the point M(0, -1) is given by:

$\displaystyle{ y-(-1)=\frac{5}{3}(x-0)$

$\displaystyle{ y+1= \frac{5}{3}x$

$\displaystyle{ 3y+3=5x$

$\displaystyle{ 5x-3y-3=0$

Answer: 5x-3y-3=0

8 0

3 years ago