Divide 132kg in a ratio of 3:3:5

1 answer:

3 0

You have to add 3+3+5.
It equals 11.
Then divide 132 by 11.
It equals 12.
Then you have to put it into the ratio, so you multiply each number by 12.
So the ratio is 36:36:60

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Describe the sampling distribution of Phat. Assume the size of the Population is 25,000. N = 500 P = 0.4 Determine the Mean of t

PIT_PIT [208]

Answer:

0.022

Step-by-step explanation:

Given that :

Population size = 25000

n = 500 ; p = 0.4

Size of random sample (n) = 500

5% of population size : 0.05 * 25000 = 1250

Distribution is normally distributed since n < 5% of population size

Hence, the mean of the distribution = p = 0.4

Standard deviation = √((pq) /n)

q = 1 - p ; q = 1 - 0. 4 = 0.6

Standard deviation = √((0.4 * 0.6) /500)

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= 0.022

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3 years ago

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3 years ago

Read 2 more answers

Solve for y 16y^2-25=0

Pepsi [2]

Answer:

$\large\boxed{x=-\dfrac{5}{4}\ \vee\ x=\dfrac{5}{4}}$

Step-by-step explanation:

$16y^2-25=0\\\\METHOD\ 1:\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\16=4^2\ \text{and}\ 25=5^2\ \text{therefore we have}\\\\4^2y^2-5^2=0\\\\(4y)^2-5^2=0\\\\(4y-5)(4y+5)+0\iff4y-5=0\ \vee\ 4y+5=0\\\\4y-5=0\qquad\text{add 5 to both sides}\\4y=5\qquad\text{divide both sides by 4}\\\boxed{y=\dfrac{5}{4}}\\\\4y+5=0\qquad\text{subtract 5 from both sides}\\4y=-5\qquad\text{divide both sides by 4}\\\boxed{x=-\dfrac{5}{4}}$

$METHOD\ 2:\\\\16y^2-25=0\qquad\text{add 25 to both sides}\\\\16y^2=25\qquad\text{divide both sides by 16}\\\\y^2=\dfrac{25}{16}\to y=\pm\sqrt{\dfrac{25}{26}}\\\\y=-\dfrac{\sqrt{25}}{\sqrt{16}}\ \vee\ x=\dfrac{\sqrt{25}}{\sqrt{16}}\\\\\boxed{y=-\dfrac{5}{4}\ \vee\ x=\dfrac{5}{4}}$