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musickatia [10]
3 years ago
15

Explain the difference between a public and Private company. is it better for a company to be public or private

Mathematics
1 answer:
Mumz [18]3 years ago
3 0
In most cases, a private company is owned by the company's founders, management, or a group of private investors. A public company is a company that has sold all or a portion of itself to the public via an initial public offering.
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Amanda has 2,00,234 dollars. She needs 4,00,578 dollars. Her friend Alice gives her 207,78 and then Amanda gives her 200 back. H
lutik1710 [3]

Answer:

sorry i dont know

Step-by-step explanation:

7 0
3 years ago
Lauren would like to have an average of 88 in her math class. There are five assignments with the following grades: 85, 100, 88,
daser333 [38]
80
85+100+88+90+95+80=528
528/6=80

7 0
3 years ago
Ashley bought 2 1/7 lb of tomatoes, 3 2/3 lb of lettuce, and 3 1/3 lb of spinach to make a salad. How many pounds of vegetables
blsea [12.9K]
9 1/7 lb

You can convert the mixed numbers to solve it easier! :)
7 0
2 years ago
While researching the cost of school lunches per week across the state, you use a sample size of 45 weekly lunch prices. The sta
Drupady [299]

We assume the lunch prices we observe are drawn from a normal distribution with true mean \mu and standard deviation 0.68 in dollars.


We average n=45 samples to get \bar{x}.


The standard deviation of the average (an experiment where we collect 45 samples and average them) is the square root of n times smaller than than the standard deviation of the individual samples. We'll write


\sigma = 0.68 / \sqrt{45} = 0.101


Our goal is to come up with a confidence interval (a,b) that we can be 90% sure contains \mu.


Our interval takes the form of ( \bar{x} - z \sigma, \bar{x} + z \sigma ) as \bar{x} is our best guess at the middle of the interval. We have to find the z that gives us 90% of the area of the bell in the "middle".


Since we're given the standard deviation of the true distribution we don't need a t distribution or anything like that. n=45 is big enough (more than 30 or so) that we can substitute the normal distribution for the t distribution anyway.


Usually the questioner is nice enough to ask for a 95% confidence interval, which by the 68-95-99.7 rule is plus or minus two sigma. Here it's a bit less; we have to look it up.


With the right table or computer we find z that corresponds to a probability p=.90 the integral of the unit normal from -z to z. Unfortunately these tables come in various flavors and we have to convert the probability to suit. Sometimes that's a one sided probability from zero to z. That would be an area aka probability of 0.45 from 0 to z (the "body") or a probability of 0.05 from z to infinity (the "tail"). Often the table is the integral of the bell from -infinity to positive z, so we'd have to find p=0.95 in that table. We know that the answer would be z=2 if our original p had been 95% so we expect a number a bit less than 2, a smaller number of standard deviations to include a bit less of the probability.


We find z=1.65 in the typical table has p=.95 from -infinity to z. So our 90% confidence interval is


( \bar{x} - 1.65 (.101),  \bar{x} + 1.65 (.101) )


in other words a margin of error of


\pm 1.65(.101) = \pm 0.167 dollars


That's around plus or minus 17 cents.




3 0
3 years ago
Read 2 more answers
Joy earns $90.00 a month babysitting. She saves 15% of the money and is able to spend the rest. How much money does she save a m
alisha [4.7K]
You have 90 and you have 15%

so you have to subtract 90 and 15%
 
90-15%=76.5

she puts $13.50 in savings and is able to spend $76.5
4 0
3 years ago
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