The answer is d. (-3,8.)
Lauren would like to have an average of 88 in her math class. There are five assignments with the following grades: 85, 100, 88,
1 answer:
You might be interested in
Area of the trapezoid:
Area of the rectangle:
4.2 x 3.1 = 13.02 cm^2
Area of each quarter circle:
We have two quarter circles:
7.54 + 7.54 = 15.08
41.65 + 13.02 + 15.08 = 69.75 cm^2
Area of the rectangle:
4.2 x 3.1 = 13.02 cm^2
Area of each quarter circle:
We have two quarter circles:
7.54 + 7.54 = 15.08
41.65 + 13.02 + 15.08 = 69.75 cm^2
Answer:
3rd choice
Step-by-step explanation:
9/5 = 18/10 = 1.8
All your numbers are between 1 and 2, and all have a fractional part that is a whole number of tenths. 1.3, 1.5, and 1.8 will be correctly shown by dots on the 3rd, 5th, and 8th marks.
Answer: The graph in the bottom right-hand corner
(see figure 4 in the attached images below)
===========================================
Explanation:
Let's start off by graphing x+y < 1. The boundary equation is x+y = 1 since we simply change the inequality sign to an equal sign. Solve for y to get x+y = 1 turning into y = -x+1. This line goes through (0,1) and (1,0). The boundary line is a dashed line due to the fact that there is no "or equal to" in the original inequality sign. So x+y < 1 turns into y < -x+1 and we shade below the dashed line. The "less than" means "shade below" when y is fully isolated like this. See figure 1 in the attached images below.
Let's graph 2y >= x-4. Start off by dividing everything by 2 to get y >= (1/2)x-2. The boundary line is y = (1/2)x-2 which goes through the two points (0,-2) and (4,0). The boundary line is solid. We shade above the boundary line. Check out figure 2 in the attached images below.
After we graph each individual inequality, we then combine the two regions on one graph. See figure 3 below. The red and blue shaded areas in figure 3 overlap to get the purple shaded area you see in figure 4, which is the final answer. Any point in this purple region will satisfy both inequalities at the same time. The solution point cannot be on the dashed line but it can be on the solid line as long as the solid line is bordering the shaded purple region. Figure 4 matches up perfectly with the bottom right corner in your answer choices.
