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Afina-wow [57]
3 years ago
15

What is the equation of the following line? Be sure to scroll down first to see

Mathematics
2 answers:
PolarNik [594]3 years ago
6 0

Answer:

y=-3x

Step-by-step explanation:

we know that the equation of the line is:

y=mx+b

m= slope= (y2-y1)/(x2-x1)

we have two points giver from the graph:

point 1: (0,0)

point 2: (3,-9)

we to find the slope:

m=(-9-0)/(3-0)

m=-3/3

m=-3

we need to find "b"

using the point (0,0)

we have

0=0x+b

so we have b=0

finally we have

y=-3x+0

y =-3x

CaHeK987 [17]3 years ago
3 0

Answer:

B

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, 0) and (x₂, y₂ ) = (3, - 9) ← 2 points on the line

m = \frac{-9-0}{3-0} = \frac{-9}{3} = - 3

Since the line passes through the origin then c = 0

y = - 3x + 0, which is simply

y = - 3x → B

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Answer:

19 > DB > 5

Step-by-step explanation:

In a triangle Δ ABC, AC = 7, and BC = 18.

Therefore, the length of the third side of the triangle Δ ABC i.e. length of AB can have a maximum value of < (7 + 18) i.e. 25 and the minimum value of the length AB will be > (18 - 7) i.e. 11

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Therefore, 25 > 6 + DB > 11

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