22a) Matts' weekly fee is $7.50. We know this is by looking at the Y-axis. If he doesn't sell any books at the beginning of the week, his earnings are at -$7.50. We can assume that he pays that much for internet fee.
22b) Matt makes $1.50 for each book he sells. We know this because if you look at (5,0) and then the next one (6, 1.5), we see that his Y-value has increased by $1.50, which is equal to one book because 6 - 5 = 1 book.
22c) y = 1.5x - 7.5
22d) I'm going to assume that question means $30 in profit. Let's plug in the 30 in the equation. 30 = 1.5x - 7.5. Simplify.
Matt has to sell 25 books to make $30
X= 22.5 get the x by itself by dividing by 2
Answer:
70 + 4D
Step-by-step explanation:
- (2 x 100) + (7 x 10) + (4 x D) + (2 x 100)
- (200) + (70) + 4D + 200
-200 + 70 +4D + 200
-130 + 4D + 200
70 + 4D
Given:
Height of the Statue of Liberty = 305 feet
Angle of elevation = 9 degrees
To find:
The between the tourist and the Statue of Liberty.
Solution:
Using the given information, draw a figure as shown below.
In a right triangle,

In the triangle ABC,




Therefore, the tourist is standing 1926 feet from the Statue of Liberty.
Answer:
As the first part comes to the rest means, then it will fall under gravity directly.
First of all maximum height,
H=
g
u²sin²θ
H=
2×10
400×(
2
1
)
H=10m.
As initially the full projectile was supposed to land at A but due to explosion first part land at A', so to make the centre of mass lies at A the second part should lie at B.
f they don't break (explode) range OA
OA=
g
u²sin2θ
OA=400×sin45×
10
2