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Romashka-Z-Leto [24]
3 years ago
13

Brett has a $30 online gift certificate. He plans to buy as many books as he can. The cost of each book is $4. There is also a s

ingle shipping charge of $2. How many books can he afford without spending more than his gift certificate amount?
Mathematics
1 answer:
kkurt [141]3 years ago
7 0

Answer:

7 books

Step-by-step explanation:

make an equation

x = # of books each book is $4 so its 4x

the shipping fee no matter how many books he buys will be $2 so it's just 2

the equation looks like this:

4x + 2 = 30

we set equal to 30 cuz he can't spend more than $30

solve for x

4x = 30 -2

4x = 28

x = 7

Brett can buy no more than 7 books.

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mestny [16]
1. No
2. Yes
3. 2 out of 6
7 0
3 years ago
Read 2 more answers
A rectangle has the length of 2x+7 and the width of 9x find the area and the perimeter
seraphim [82]

Answer:

see explaination

Step-by-step explanation:

length (l) = 2x+7

width (b) = 9x

area of rectangle = l×b

=(2x+7)(9x)

=18x^2+63x

perimeter of rectangle = 2(l+b)

=2(2x+7)(9x)

=2(18x^2+63x)

=36x^2+126x

3 0
2 years ago
A sample of 100 workers located in Atlanta has an average daily work time of 6.5 hours with a standard deviation of 0.5 hours. A
Readme [11.4K]

Answer:

t=\frac{6.5-6.7}{\sqrt{\frac{0.5^2}{100}+\frac{0.7^2}{110}}}}=-2.398  

df = n_1 +n_2 -2= 100+110-2= 208

Since is a bilateral test the p value would be:

p_v =2*P(t_{208}

Comparing the p value with the significance level given \alpha=0.05 we see that p_v so we can conclude that we can reject the null hypothesis, and we have significant differences between the two groups at 5% of significance.

Step-by-step explanation:

Data given and notation

\bar X_{1}=6.5 represent the sample mean for Atlanta

\bar X_{2}=6.7 represent the sample mean for Chicago

s_{1}=0.5 represent the sample deviation for Atlanta

s_{2}=0.7 represent the sample standard deviation for Chicago

n_{1}=100 sample size for the group Atlanta

n_{2}=110 sample size for the group Chicago

t would represent the statistic (variable of interest)

\alpha=0.01 significance level provided

Develop the null and alternative hypotheses for this study?

We need to conduct a hypothesis in order to check if the meanfor atlanta is different from the mean of Chicago, the system of hypothesis would be:

Null hypothesis:\mu_{1}=\mu_{2}

Alternative hypothesis:\mu_{1} \neq \mu_{2}

Since we don't know the population deviations for each group, for this case is better apply a t test to compare means, and the statistic is given by:

t=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}} (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Calculate the value of the test statistic for this hypothesis testing.

Since we have all the values we can replace in formula (1) like this:

t=\frac{6.5-6.7}{\sqrt{\frac{0.5^2}{100}+\frac{0.7^2}{110}}}}=-2.398  

What is the p-value for this hypothesis test?

The degrees of freedom are given by:

df = n_1 +n_2 -2= 100+110-2= 208

Since is a bilateral test the p value would be:

p_v =2*P(t_{208}

Based on the p-value, what is your conclusion?

Comparing the p value with the significance level given \alpha=0.05 we see that p_v so we can conclude that we can reject the null hypothesis, and we have significant differences between the two groups at 5% of significance.

3 0
3 years ago
Read 2 more answers
Suppose box A contains 4 red and 5 blue poker chips and box B contains 6 red and 3 blue poker chips. Then a poker chip is chosen
sergejj [24]

Answer:

0.5172 = 51.72% probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Coin chosen from box B is red.

Event B: Blue poker chip transferred.

Probability of choosing a red coin:

7/10 of 4/9(red coin from box A)

6/10 of 5/9(blue coin from box A). So

P(A) = \frac{7}{10}*\frac{4}{9} + \frac{6}{10}*\frac{5}{9} = \frac{28 + 30}{90} = 0.6444

Blue chip transferred, red coin chosen:

6/10 of 5/9. So

P(A \cap B) = \frac{6}{10}*\frac{5}{9} = \frac{30}{90} = 0.3333

What is the probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.3333}{0.6444} = 0.5172

0.5172 = 51.72% probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red

5 0
3 years ago
Write the expression in word form 12÷6×2
finlep [7]

Answer:

Twelve divide by six times two.

4

Step-by-step explanation:

To solve this problem, first you have to use the order of operations stands for parenthesis, exponents, multiply, divide, add, and subtract from left to right.

First, multiply & divide numbers from left to right.

\displaystyle 12\div6\times2

\displaystyle 12\div6=2

\displaystyle 2\times2=4

Therefore, the correct answer is twelve divide by six times two or 4.

<h2>Hope this helps!</h2><h2 /><h2>Have a wonderful blessing day! :)</h2><h2 /><h2>Good luck! :)</h2>
6 0
3 years ago
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