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julsineya [31]
3 years ago
7

The diameter of a semicircle is 2 feet. What is the semicircle's perimeter?

Mathematics
1 answer:
Mice21 [21]3 years ago
6 0

Answer:

11/7 feet

Step-by-step explanation:

the perimeter of a circle is πr²

and a semi circle is half of a circle then the formula would be 1/2 πr²

1/2×22/7×1 (it is 1 because we have divided the diameter to get radius

so we derived at 11/7

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What is the slope-intercept form for a line that passes through (4,3) and is parallel to x=0
nikitadnepr [17]

Answer:

x=4

Step-by-step explanation:

x=0 is an undefined slope(straight line vertically)

We need the line to pass through the point (4,3)

So, we just take the x coordinate from the equation and make it also have an undefined slope.

x = 4

6 0
4 years ago
Which equation represents the linear relationships shown in the table?
saveliy_v [14]

Answer:

idk

Step-by-step explanation:

4 0
3 years ago
Select the expression that shows the application of the distributive property for
sergeinik [125]

Answer:

c. 9t+45 that shows distributive property

where it shows a*(b+c)=(a*b)+(b*c).so,9(t+5)=9*t+9*5

8 0
3 years ago
A ball is tossed up in the air at an initial rate of 50 ft/sec from 5 ft off the ground.
Fofino [41]

Answer with Step-by-step explanation:

Since we have given that

Initial velocity = 50 ft/sec = v_0

Initial height of ball = 5 feet = h_0

a. What type of function models the height (ℎ, in feet) of the ball after tt seconds?

As we know the function for height h with respect to time 't'.

h(t)=-16t^2+v_0t+h_0\\\\h(t)=-16t^2+50t+5

b. Explain what is happening to the height of the ball as it travels over a period of time (in tt seconds).

What function models the height, ℎ (in feet), of the ball over a period of time (in tt seconds)?

if it travels over a period of time then time becomes continuous interval . so it will use integration over a period of time

Our function becomes,

h(t)=\int\limits^t_0 {-16t^2+50t+5} \, dt

3 0
3 years ago
FInd the value of x.<br> Y<br> D<br> W<br> X<br> (15x-8)<br> X =<br> N<br> 226
Oksi-84 [34.3K]

Let's start with the given arc and its angle.

The angle YWX is going to be half the arc length.

YWX = 1/2 (226) = 113

Angles VWX and YWX form a linear pair (or are supplementary angles), which means that their sum is 180 degrees.

(15x - 8) + 113 = 180

15x + 105 = 180

15x = 75

x = 5

Hope this helps!

8 0
2 years ago
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