Find the area AND perimeter of this shape.

What are the next three terms 4, 7/4,-1/2,-11/4...

Molodets [167]

Answer:

{-29/4, -19/2, -47/4}

Step-by-step explanation:

Note that this is a decreasing arith. seq. Each term is smaller than the previous term, the result of the subtraction of 2 1/4 (equivalent to 9/4).

The fourth term is -11/4; subtracting 9/4 results in -20/4, or -5.

The fifth term is -20/4; subtracting 9/4 results in -29/4.

The 6th term is -29/4; subtracting 9/4 results in -38/4, or -19/2.

The 7th term is -38/4; subtracting 9/4 results in -47/4.

Thus, the "next three terms" following the first four terms are {-29/4, -19/2, -47/4}

5 0

3 years ago

2. Find the Unit price per can if it cots $3 for 6 cans of sodas. Round To the nearest hundredths. $0.5 per can $0.6 per can

Sav [38]

Hey there! I'm happy to help!

We see that it costs $3 for 6 cans of sodas. We want to find how much it costs for 1 can of soda. To do this, we simply divide by 6!

3/6=0.5

The unit price per can is $0.5 per can.

Have a wonderful day! :D

5 0

3 years ago

A reflection across the line y= x occurs to the preimage point (2,2). What is the image of the point after the transformation

dsp73

Answer:

big brain time

Step-by-step explanation:

2.2

dont quote me, im 2.

6 0

3 years ago

How to add/subtract like radical expressions?

N76 [4]

9514 1404 393

Explanation:

"Like" radicals can be added and subtracted in the same way any like terms can be combined. It can be helpful to simplify the radical as much as possible so that it can be seen whether the radicals are "like" or not.

<u>Examples</u>:

√2 +√3 . . . . cannot be combined

√2 +√8 = √2 +2√2 = 3√2 . . . . the simplified radicals can be combined

4 0

3 years ago

A sample of 100 workers located in Atlanta has an average daily work time of 6.5 hours with a standard deviation of 0.5 hours. A

Readme [11.4K]

Answer:

$t=\frac{6.5-6.7}{\sqrt{\frac{0.5^2}{100}+\frac{0.7^2}{110}}}}=-2.398$

$df = n_1 +n_2 -2= 100+110-2= 208$

Since is a bilateral test the p value would be:

$p_v =2*P(t_{208}$

Comparing the p value with the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we can reject the null hypothesis, and we have significant differences between the two groups at 5% of significance.

Step-by-step explanation:

Data given and notation

$\bar X_{1}=6.5$ represent the sample mean for Atlanta

$\bar X_{2}=6.7$ represent the sample mean for Chicago

$s_{1}=0.5$ represent the sample deviation for Atlanta

$s_{2}=0.7$ represent the sample standard deviation for Chicago

$n_{1}=100$ sample size for the group Atlanta

$n_{2}=110$ sample size for the group Chicago

t would represent the statistic (variable of interest)

$\alpha=0.01$ significance level provided

Develop the null and alternative hypotheses for this study?

We need to conduct a hypothesis in order to check if the meanfor atlanta is different from the mean of Chicago, the system of hypothesis would be:

Null hypothesis: $\mu_{1}=\mu_{2}$

Alternative hypothesis: $\mu_{1} \neq \mu_{2}$

Since we don't know the population deviations for each group, for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}}$ (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Calculate the value of the test statistic for this hypothesis testing.

Since we have all the values we can replace in formula (1) like this:

$t=\frac{6.5-6.7}{\sqrt{\frac{0.5^2}{100}+\frac{0.7^2}{110}}}}=-2.398$

What is the p-value for this hypothesis test?

The degrees of freedom are given by:

$df = n_1 +n_2 -2= 100+110-2= 208$

Since is a bilateral test the p value would be:

$p_v =2*P(t_{208}$

Based on the p-value, what is your conclusion?

Comparing the p value with the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we can reject the null hypothesis, and we have significant differences between the two groups at 5% of significance.

3 0

3 years ago

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