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eduard
3 years ago
14

Find the area AND perimeter of this shape.

Mathematics
1 answer:
RoseWind [281]3 years ago
3 0

Answer:

Area: 2206.86 square m

Perimeter: 194.25 m

Step-by-step explanation:

Area:

30 x 50 = 1500 square m

30/2 = 15 = the radius of the semi circles

pi x 15^2 = 706.86 square m

1500 + 706.86 = 2206.86 square m

Perimeter:

pi x 15 x 2 = 94.25 m

94.25 (perimeter of both semi circles) + (50 x 2) = 194.25 m

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Solve and check: 1 x + 3 = x + 10 x − 2 From least to greatest, the solutions are x = and x = .
blondinia [14]

Answer:

x= 1/2

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

1x+3=x+10x−2

x+3=x+10x+−2

x+3=(x+10x)+(−2)(Combine Like Terms)

x+3=11x+−2

x+3=11x−2

Step 2: Subtract 11x from both sides.

x+3−11x=11x−2−11x

−10x+3=−2

Step 3: Subtract 3 from both sides.

−10x+3−3=−2−3

−10x=−5

Step 4: Divide both sides by -10.

−10x/−10=−5/−10x=1/2

8 0
3 years ago
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Fins the product of (3s+2t)(3s-3t)
erastovalidia [21]
Your answer is 9s^2-9st+6st-6t^2
6 0
4 years ago
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-x²-8x-16=0 <br>what is the solutions by solving by quadratic equations ​
Alika [10]

Answer:

x = - 4

Step-by-step explanation:

Given

- x² - 8x - 16 = 0 ( multiply through by - 1 to clear the leading negative )

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6 0
3 years ago
Help asap plz ill give a gold medal. the label on cars antifreeze claims to protect the car between -30celsius and 130celsius. t
irga5000 [103]
The inequality would start out looking like this:
-30\ \textless \  \frac{5}{9} (F-32)\ \textless \ 130
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-270\ \textless \ 5(F-32)\ \textless \ 1170
Then distribute the 5 into the parenthesis:
-270\ \textless \ 5F-160\ \textless \ 1170
Now add 160 everywhere:
-110\ \textless \ 5F\ \textless \ 1330
and finally divide everything by 5:
-22<F<266


4 0
3 years ago
Find the product. 4x - 3y(-2x 2y)
liubo4ka [24]
(4x + 3y)² = 

<span>(4x)² + 2 (4x) (3y) + (3y)² = </span>

<span>16x² + 24xy + 9y²</span>
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3 years ago
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