Answer:
the probability that the mean student loan debt for these people is between $31000 and $33000 is 0.1331
Step-by-step explanation:
Given that:
Mean = 30000
Standard deviation = 9000
sample size = 100
The probability that the mean student loan debt for these people is between $31000 and $33000 can be computed as:





From Z tables:


Therefore; the probability that the mean student loan debt for these people is between $31000 and $33000 is 0.1331
Answer:
2x^4-11x^3+68x-80
2x^4-4x^3-7x^3+14x^2-14x^2+28x+40x-80
2x^3(x-2)-7x^2(x-2)-14x(x-2)+40(x-2)
(x-2)(2x^3-7x^2-14x+40)
(x-2)(2x^3-4x^2-3x^2+6x-20x+40)
(x-2)(2x^2(x-2)-3x(x-2)-20(x-2))
(x-2)(x-2)(2x^3-3x-20)
(x-2)(x-2)(2x^2+5x-8x-20)
(x-2)(x-2)(x(2x+5)-4(2x+5))
(x-2)(x-2)(2x+5)(x-4)
(x-2)^2(2x+5)(x-4)
The hypothesis shows that we have evidence that the proportion surviving after eating organic is higher.
<h3>How to illustrate the information?</h3>
The following can be deduced from the information:
x1 = 275
x2 = 170
n1 = 500
n2 = 500
The sample proportion will be:
p1 = 275/500 = 0.55
p2 = 170/500 = 0.34
The pooled proportion will be:
= (275 + 170)/(500 + 500)
= 0.44
The test statistic is 6.681. It should be noted that the test statistics is a number that's calculated by a statistical test. It shows how the observed data are far from the null hypothesis.
The p value in this scenario is extremely small. The p value is a measurement used to validate a hypothesis against the observed data. Therefore, we have to reject the null hypothesis.
In this case, the hypothesis shows that we have evidence that the proportion surviving after eating organic is higher.
Learn more about hypothesis on:
brainly.com/question/15980493
#SPJ1
Answer:
c=
Step-by-step explanation:
a=height=6
b=length=4
using pythagorean theorem
a^2+b^2=c^2
36+16=c^2
c=
c=