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Westkost [7]
3 years ago
14

Is this answer correct on problem 3

Mathematics
2 answers:
Yuri [45]3 years ago
6 0
-1/4*x^2-x+3=-1/4*(x^2+4x)+3=-1/4*(x^2+4x+4)+4=-1/4*(x+2)^2+4
x0=-2
charle [14.2K]3 years ago
3 0
This is a vertical parabola which opens downwards

Use the formula

4p(y - k) =  (x - h^2

converting to  vertex form-
y =
-1/4(x^2 + 4x) + 3
y = -1/4[ (x + 2)^2] + 4

y - 4  =  -1/4 (x + 2)^2

-4(y - 4) =  (x + 2)^2  so the vertex is at (-2, 4)
comparing with the above formula
4p = -4
so p = -1  where p is the distance of the focus from the vertex
The vertex is at  (-2,4)  so the focus is at  (-2, 4-1)  = (-2, 3) Answer

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Solve the system of equations.<br><br> 14x + y = −4<br><br> y = 3x^2 − 11x − 4
sveta [45]
You can use substitution here. First, get y alone:

14x + y = -4
subtract 14x from each side
y = -4 - 14x

Then, plug y into the second equation

-4 - 14x = 3x² - 11x - 4
 then solve from there

Hope this helps :)
4 0
3 years ago
7/3*+1/3=4+5/3x this is a test pls helppp
Andreyy89

Answer:

I am sorry. To answer a test is against the Honor Code, I cannot help you.

Step-by-step explanation:

Remember PEMDAS :)

3 0
3 years ago
Read 2 more answers
Expand the following using the Binomial Theorem and Pascal’s triangle. (x + 2)6 (x − 4)4 (2x + 3)5 (2x − 3y)4 In the expansion o
ivolga24 [154]
\bf (2x+3)^5\implies &#10;\begin{array}{llll}&#10;term&coefficient&value\\&#10;-----&-----&-----\\&#10;1&&(2x)^5(+3)^0\\&#10;2&+5&(2x)^4(+3)^1\\&#10;3&+10&(2x)^3(+3)^2\\&#10;4&+10&(2x)^2(+3)^3\\&#10;5&+5&(2x)^1(+3)^4\\&#10;6&+1&(2x)^0(+3)^5&#10;\end{array}

as you can see, the terms exponents, for the first term, starts at highest, 5 in this case, then every element it goes down by 1, till it gets to 0

for the second term, starts at 0, and every element it goes up by 1, till it gets to the highest

now, to get the coefficient, they way I get it, is "the product of the current coefficient and the exponent of the first term, divided by the exponent of the second term plus 1"

notice the first coefficient is always 1

so...how did we get 10 for the 3rd element?  well, 5*4/2
how did we get 10 for the fourth element?  well, 10*2/4


\bf (2x-3y)^4\implies &#10;\begin{array}{llll}&#10;term&coefficient&value\\&#10;-----&-----&-----\\&#10;1&&(2x)^4(-3y)^0\\&#10;2&+4&(2x)^3(-3y)^1\\&#10;3&+6&(2x)^2(-3y)^2\\&#10;4&+4&(2x)^1(-3y)^3\\&#10;5&+1&(2x)^0(-3y)^4&#10;\end{array}


\bf (3a+4b)^8\implies &#10;\begin{array}{llll}&#10;term&coefficient&value\\&#10;-----&-----&-----\\&#10;1&&(3a)^8(+4b)^0\\&#10;2&+8&(3a)^7(+4b)^1\\&#10;3&+28&(3a)^6(+4b)^2\\&#10;4&+56&(3a)^5(+4b)^3\\&#10;5&+70&(3a)^4(+4b)^4\\&#10;6&+56&(3a)^3(+4b)^5\\&#10;7&+28&(3a)^2(+4b)^6\\&#10;8&+8&(3a)^1(+4b)^7\\&#10;9&+1&(3a)^0(+4b)^8&#10;\end{array}

and from there, you can simplify the elements of the expansion by combining the coefficients

like for example, the 7th element of (3a+4b)⁸ will then be 1032192a²b⁶
7 0
3 years ago
Read 2 more answers
1 point
photoshop1234 [79]

Answer:

 b

Step-by-step explanation:

done it

5 0
3 years ago
Help please..........
dem82 [27]

Answer:

Step-by-step explanation:

x is greater then -2

3 0
3 years ago
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