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lbvjy [14]
3 years ago
15

Convert (1/3)^x=27 to logarithmic form, with work worked out!

Mathematics
1 answer:
Sophie [7]3 years ago
6 0

{a}^{x}  = m \\  log_{a}(m)  = x

( \frac{1}{3} )^{x}  = 27 \\  log_{ \frac{1}{3} }(27)  = x

That's the logarithmic form. Do you need with solving the equation too?

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An EPA contractor needs to test the concentration of a substance in ten samples of the ground water. Seventy samples were
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Systematic sampling

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An EPA contractor needing to test the concentration of a substance in ten samples out seventy samples provided form a single source at regular time intervals.

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A ball is thrown into the air by a baby alien on a planet in the system of Alpha Centauri with a velocity of 43 ft/s. Its height
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Answer:

Instantaneous Velocity at t = 1 is 20 feet per second

Step-by-step explanation:

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y(t)=43t-23t^{2}

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Average velocity =

\displaystyle\frac{\text{Displacement}}{\text{Time}}

1) 0.01

y(1 + 0.01)=y(1.01) = 43(1.01)-23(1.01)^{2} = 19.9677\\\\\text{Average Velocity} = \dfrac{y(1.01)-y(1)}{1.01-1} =\dfrac{19.9677-20}{1.01-1}= \dfrac{-0.0323}{0.01} = -3.230000 \text{feet per second}

2) 0.005 s

y(1 + 0.005)=y(1.005) = 43(1.005)-23(1.005)^{2} = 19.984425\\\\\text{Average Velocity} = \dfrac{y(1.005)-y(1)}{1.005-1} =\dfrac{19.984425-20}{1.005-1} = -3.1150000 \text{feet per second}

3) 0.002 s

y(1 + 0.002)=y(1.002) = 43(1.002)-23(1.002)^{2} = 19.993908\\\\\text{Average Velocity} = \dfrac{y(1.002)-y(1)}{1.002-1} =\dfrac{19.993908-20}{1.002-1} = -3.0460000 \text{feet per second}

4) 0.001 s

y(1 + 0.001)=y(1.001) = 43(1.001)-23(1.001)^{2} = 19.996977\\\\\text{Average Velocity} = \dfrac{y(1.001)-y(1)}{1.001-1} =\frac{19.996977-20}{1.001-1} = -3.0230000 \text{feet per second}

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3 years ago
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