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aleksley [76]
3 years ago
11

Use act it out strategy!! Please help me.

Mathematics
1 answer:
Sav [38]3 years ago
5 0
1. 2.22
2. 4.95
For the 4 you devide 50 by 6 and for 5 you subtract
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Write and solve a real-world problem that can be modeled by the equation 0.75x-18.50=0.65x Finding X the variable
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I got x=185

0.75(185)-18.50=0.65(185)

120.25=120.25
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the area of a rectangular back yard is given by the trinomial b^2+5b-24. What are possible dimensions of the backyard?
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B^2+5b-24 Using the AC method for factoring (b+8)(b-3)
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At a canning facility, a technician is testing a machine that is supposed to deliver 250 milliliters of product. The technician
Serhud [2]

Answer:

The value of the test statistic is t = 1.97

Step-by-step explanation:

The null hypothesis is:

H_{0} = 250

The alternate hypotesis is:

H_{1} \neq 250

Our test statistic is:

t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the null hypothesis value, \sigma is the standard deviation and n is the size of the sample.

In this problem:

X = 251.6, \mu = 250, \sigma = 5.4, n = 44

So

t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

t = \frac{251.6 - 250}{\frac{5.4}{\sqrt{44}}}

t = 1.97

The value of the test statistic is t = 1.97

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3 years ago
What is the aswer ??????​
svet-max [94.6K]

Answer:

A prime numbers are numbers which have only two factor

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Three six-sided fair dice are rolled. The six sides of each die are numbered 1; 2; : : : ; 6. Let A be the event that the first
valkas [14]

Answer:

1.) [A, B, C]

2.) [A', B', C']

3.) [A', B, C] or [A, B', C] or [A, B, C'] or [ A', B', C] or [A', B, C'] or [A, B', C'] or [A', B', C']

4.) A', B', C] or [A', B, C'] or [A, B', C'] or [A', B, C] or [A, B', C] or [A, B, C'] or [A, B, C]

Step-by-step explanation:

If A is the event that the first die shows an even number, then A' is the event that first die DOES NOT show an even number.

If B is the event that the Second die shows and even number, then B' is the event that second die DOES NOT show an even number.

If C is the event that the third die shows an even number, then C' is the event that third die DOES NOT show an even number.

Hence, our possible events are A, A', B, B', C, C'.

For question 1, in the event that all three dice show and even number, the expression of the event = [A, B, C]

For question two, in the event that no die shows an even number, the expression of the event = [A', B', C']

For question 3,In the event that at least one die shows an odd number, the expression of the event = [A', B, C] or [A, B', C] or [A, B, C'] or [ A', B', C] or [A', B, C'] or [A, B', C'] or [A', B', C']

For question 4,in the event that at most two dice show odd numbers, the expression of the event = [A', B', C] or [A', B, C'] or [A, B', C'] or [A', B, C] or [A, B', C] or [A, B, C'] or [A, B, C]

6 0
3 years ago
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