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aleksley [76]
3 years ago
11

Use act it out strategy!! Please help me.

Mathematics
1 answer:
Sav [38]3 years ago
5 0
1. 2.22
2. 4.95
For the 4 you devide 50 by 6 and for 5 you subtract
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3.x4 - 2x2 + 15.x2<br> Which product Is the factored form of the polynomial
Dmitry_Shevchenko [17]

Answer:

3*4=12

12-2=10

10*2=20

20+15=35

35*2=70

Step-by-step explanation:

4 0
3 years ago
A football is thrown from the top of the stands, 50 feet above the ground at an initial velocity of 62 ft/sec and at an angle of
Anvisha [2.4K]

a. i. The parametric equation for the horizontal movement is x = 43.84t

ii. The parametric equation for the vertical movement is y = 50 + 43.84t

b. the location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

<h2>a. Parametric equations</h2>

A parametric equation is an equation that defines a set of quantities a functions of one or more independent variables called parameters.

<h3>i. Parametric equation for the horizontal movement</h3>

The parametric equation for the horizontal movement is x = 43.84t

Since

  • the angle of elevation is Ф = 45° and
  • the initial velocity, v = 62 ft/s,

the horizontal component of the velocity is v' = vcosФ.

So, the horizontal distance the football moves in time, t is x = vcosФt

= vtcosФ

= 62tcos45°

= 62t × 0.7071

= 43.84t

So, the parametric equation for the horizontal movement is x = 43.84t

<h3>ii Parametric equation for the vertical movement</h3>

The parametric equation for the vertical movement is y = 50 + 43.84t

Also, since

  • the angle of elevation is Ф = 45° and
  • the initial velocity, v = 62 ft/s,

the vertical component of the velocity is v" = vsinФ.

Since the football is initially at a height of h = 50 feet, the vertical distance the football moves in time, t relative to the ground is y = 50 + vsinФt

= 50 + vtcosФ

= 50 + 62tsin45°

= 50 + 62t × 0.7071

= 50 + 43.84t

<h3>b. Location of football at maximum height relative to starting point</h3>

The location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

Since the football reaches maximum height at t = 1.37 s

The x coordinate of its location at maximum height is gotten by substituting t = 1.37 into x = 48.84t

So, x = 43.84t

x = 43.84 × 1.37

x = 60.0608

x ≅ 60.1 ft

The y coordinate of the football's location at maximum height relative to the ground is y = 50 + 48.84t

The y coordinate of the football's location at maximum height relative to the starting point is y - 50 = 48.84t

So,  y - 50 = 48.84t

y - 50 = 43.84 × 1.37

y - 50 = 60.0608

y - 50 ≅ 60.1 ft

So, the location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

Learn ore about parametric equations here:

brainly.com/question/8674159

5 0
2 years ago
DONT FORGET TO GRAPH IT!! ALL ANSWERS THAT DONT ANSWER MY QUESTION, WILL BE REPORTED!
DaniilM [7]

Answer:

n ≥ 1/4

Step-by-step explanation:

I wish I could add a picture, but I can't, so you'll have to graph it by yourself.

6 0
3 years ago
Lamar plans to watch 2 movies each month.write an equation represent the total number of movies n that he will watch I m moths
grandymaker [24]

Answer:

n=2m

Step by step:

total=rate of movie watching per month times months

n=2 movies per month times 'm' months, so,

n=2m

4 0
3 years ago
Read 2 more answers
What is y 12y - 19= 6y+1=
nadezda [96]

Answer:

<h2><u><em>Y= 10/3 or 3.333....</em></u></h2>

Step-by-step explanation:

12y-19= 6y+1

12y-6y = 1 +19

6y = 20

y = 20/6

y= 10/3 or 3.33..

 

<h2><u><em>HAVE A NICE TIME :)</em></u></h2><h2><em>pls give a </em><u><em>brainliest</em></u><em> if it is CORRECT</em></h2>
3 0
2 years ago
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