Polynomials are <em>algebraic</em> expressions whose <em>standard</em> form is defined below:
The expression p(x) = - 13 represents a <em>zeroeth</em> polynomial.
<h3>What is a polynomial?</h3>
Herein we must present what the form of polynomials are. Polynomials are <em>algebraic</em> expressions whose <em>standard</em> form is defined below:
(1)
Where:
- i-th coefficient- n - Grade
- x - Independent variable
An example is the expression p(x) = - 13, <em>real </em>numbers can be define as <em>zeroeth</em> polynomials. In this regard, the example can be seen as:
p(x) = 0 · xⁿ + 0 · xⁿ⁻¹ + ... + 0 · x² + 0 · x - 13
<h3>Remark</h3>
The statement is incomplete. We decided to re-define the statement to what polynomials are.
To learn more on polynomials: brainly.com/question/11536910
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Answer:
i think the answer in 14
Step-by-step explanation:
:)
Answer:
B
Step-by-step explanation:
Answer:
D. 8
Step-by-step explanation:
32^(3/5) is the same as ![\sqrt[5]{32}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B32%7D)
^3.
= 2 because 2^5=32
2^3 = 8
Answer:
A C
Step-by-step explanation:
A
A is true.The numerator does have 3 terms. The constant term (the 3 at the end) is still a term and counts as a term.
B
A constant term does not count as a coefficient so b is not right, just as you have indicated by not underlining it.
C
C is true. In fact, 2 is the leading coefficent of the denominator.
D
Either A is true or D is, but I don't think they both are. You need a modifier to claim that D is true. If the statement said the numerator has <em>at least </em>2 terms then both A and D would be true. Without the at least, you have to pick one and the one I choose is A
E
This is the tough one. Very sticky. You would think it is true, but it isn't. A constant term is not a coefficient. Coefficients only count when they are with "x"s.
