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Jlenok [28]
3 years ago
12

Which investment does not guarantee you will get your money back.

Business
2 answers:
ddd [48]3 years ago
5 0
Stock is the answer so b
Katarina [22]3 years ago
3 0
I believe it is Stock
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Alison's dress shop buys dresses from McGuire Manufacturing. Alison purchased dresses from McGuire on July 17 and received an in
aivan3 [116]

Answer:

Answer not available.

Explanation:

I did this equation and i got 5,880, and i do believe that my work is correct but it may not be so.....

7 0
3 years ago
A ________ is a collection of tasks, steps, or activities that are performed, usually in a specific order, and result in an end
harina [27]

Answer:

b

Explanation:

A process is a collection of tasks,steps,or activities that are performed

3 0
2 years ago
Mia Lane bought a high-definition television for $7,500. Based on her income, she could afford to pay back only $600 per month.
lina2011 [118]

Answer:

$ 7,012.50

Explanation:

Please see attachment

6 0
3 years ago
A time standard was set as 0.20 hour per unit based on the 20th unit produced. Assume the task has a 60 percent learning curve.
Sliva [168]

Answer:

40th unit = 0.11 hr

80th unit = 0.06 hr

160th unit = 0.03 hr

Explanation:

Given :

$T_{20} = 0.2$

Learning rate = 60% = 0.6 (r)

Now using the learning curve equation,

$ T_n = T_1(n)^b$

where b is  $b= \frac{\ln r}{\ln 2} = \frac{\ln 0.6}{\ln 2} $  = -0.833

Now

$ T_{20} = T_1(20)^{-0.833}$

$ 0.20 = T_1 (0.0824)$

$T_1$ = 2.5

For 40th unit

$ T_{40} = 2.5(40)^{-0.833}$

      = 0.11 hrs

For 80th unit

$ T_{80} = 2.5(80)^{-0.833}$

      = 0.06 hrs

For 160th unit

$ T_{160} = 2.5(160)^{-0.833}$

        = 0.03 hr

6 0
3 years ago
A company used straight-line depreciation for an item of equipment that cost $16,950, had a salvage value of $4,200, and had a f
madreJ [45]

Answer:

Annual depreciation= $2,480

Explanation:

Giving the following information:

Total Purchase price= $16,950

Useful life= 5 years

Residual value= $4,200

<u>First, we need to calculate the accumulated depreciation at the end of year 3.</u>

Annual depreciation= (Total Purchase price - salvage value)/estimated life (years)

Annual depreciation= (16,950 - 4,200) / 5

Annual depreciation= $2,550

Accumulated depreciation= 2,550*3= $7,650

<u>Now, we can calculate the new depreciation expense:</u>

Depreciable value= 16,950 - 7,650= $9,300

Useful life= 3 years

Salvage value= $1,860

Annual depreciation= (9,300 - 1,860) / 3

Annual depreciation= $2,480

4 0
3 years ago
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