F=72
g=6
------------

Therefore:


But what is e?
E=76
G=32
g=6
And:

Which means that:

If you take this value into account, you will discover that f is...

So I would have to say that the answer is approximately (c).
3a^2 B^3 C^-2 OVER a^-3 b^6 c^3
Answer:
f(x) = - 8
Explanation:
The given function is
f(x) =2x^2 -4x -6
The first step is to find the derivative of the function. Recall, if
y = ax^b
y' = abx^(b - 1)
Thus,
f'(x) = 4x - 4
We would equate f'(x) to zero and solve for x. We have
4x - 4 = 0
4x = 4
x = 4/4
x = 1
We would substitute x = 1 into the original function and solve for f(x) or y. It becomes
f(1) =2(1)^2 -4(1) - 6 = 2 - 4 - 6
f(1) = - 8
Thus, the minimum value is f(x) = - 8
Answer:
It can be found the Pythagoreus therom If you like my answer than please mark me brainliest thanks