Answer:
What is the question is this Geometry?
Step-by-step explanation:
Answer:
Step-by-step explanation:
You only need two points on a line to find the equation for that line.
We are going to use 2 points that cross that line or at least come close to. You don't have to use the green points... just any point on the line will work. You might have to approximate a little.
I see ~(67.5,67.5) and ~(64,65).
Now once you have your points, we need to find the slope.
You may use 
where 
are points on the line.
Or you can line up the points vertically and subtract then put 2nd difference over 1st difference.
Like this:
( 64 , 65 )
-( 67.5, 67.5 )
--------------------
-3.5 -2.5
So the slope is -2.5/-3.5=2.5/3.5=25/35=5/7.
Now use point-slope form to find the equation:
where 
is the slope and 
is a point on the line.
Distribute:
Simplify:
Add 65 on both sides:
Simplify:
Answer:
AB = AH
Step-by-step explanation:
Hope This Helps!!
Answer: 480
Step-by-step explanation:
8x6x10=480
48x10
480
Answer:
Step-by-step explanation:
All other things being equal (and there are a lot of other things) the 50 gram mass will show a larger temperature
increase than the 100 gram mass.
Why?
The formula is the same from both masses of water (50 grams and 100 grams)
The amount of heat added is the same. (Instead of using hot water, we'll a hot plate on a very low temperature but above what they are now.).
We'll leave it on until we see a rise in temperature delta(t1) = 10 degrees
mc delta(t) = m1 * c * delta(t1)
m = 100
m1 = 50 grams.
c is going to be divided out
we'll solve for the ratio of delta(t) / delta(t1)
100 * delta(t) = 50 (delta(t1)
100 * delta(t) = 50*10
delta(t) = 50*10/100
delta(t) = 5 degrees.
Though this may look rather convoluted, the result is telling us is that delta(t1) for the 50 gram mass is twice as big as as for the 100 gram mass.
The 100 gram mass only rises 5 degrees.
The 50 gram mass rises 10 degrees.
