Answer:
A. ![\left[\begin{array}{cc}0.93&0.07&\\0.01&0.99&\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D0.93%260.07%26%5C%5C0.01%260.99%26%5Cend%7Barray%7D%5Cright%5D)
B. (0.85 0.15)
C. 79.2% population in the city while 20.8% population in the suburb
Step-by-step explanation:
(a) The transition matrix for the information is
C S
(b) the probability vector for the information is
![(\frac{85}{100} \ \ \frac{15}{100} )](https://tex.z-dn.net/?f=%28%5Cfrac%7B85%7D%7B100%7D%20%20%5C%20%5C%20%20%20%5Cfrac%7B15%7D%7B100%7D%20%29)
and this gives us
(0.85 0.15)
(c) we simply multiply the above two matrices to find the percent of the population can be expected to be in each category after one year after
in the city there are 79.2% while in the suburb, there are 20.8%
Answer:
B.
Step-by-step explanation:
6 is left after crossing from end to end.
To find out the last operation, we must solve the entire problem.
We are given:
![\frac{5+(-8)}{-3+(-9)(-6)}](https://tex.z-dn.net/?f=%5Cfrac%7B5%2B%28-8%29%7D%7B-3%2B%28-9%29%28-6%29%7D)
Let's simplify the signs so they don't clutter our equation.
![\frac{5-8}{-3+(-9)(-6)}](https://tex.z-dn.net/?f=%5Cfrac%7B5-8%7D%7B-3%2B%28-9%29%28-6%29%7D)
We always need to be sure to use PEMDAS. Since there is no expression to solve in parenthesis and no exponents are present, we will move on to multiplication. We can multiply -9 and -6 in the denominator. When we do that, we get:
![\frac{5-8}{-3+54}](https://tex.z-dn.net/?f=%5Cfrac%7B5-8%7D%7B-3%2B54%7D)
Next, all you need to do is combine like terms in the numerator and the denominator.
![\frac{-3}{51}](https://tex.z-dn.net/?f=%5Cfrac%7B-3%7D%7B51%7D)
Simplify.
![-\frac{1}{17}](https://tex.z-dn.net/?f=-%5Cfrac%7B1%7D%7B17%7D)
To answer the question, the last operation to be performed when finding the value would be division.
Answer:
![x = 4 + \sqrt{19}](https://tex.z-dn.net/?f=x%20%3D%204%20%2B%20%5Csqrt%7B19%7D)
Step-by-step explanation:
To solve by factoring, complete the square by dividing 8 from 8x in 2. Then square the result 4 to get 16. Add 16 to both sides.
![x^2 -8x = 3\\\\x^2 - 8x + 16 = 3 + 16\\\\(x-4)^2 = 19](https://tex.z-dn.net/?f=x%5E2%20-8x%20%3D%203%5C%5C%5C%5Cx%5E2%20-%208x%20%2B%2016%20%3D%203%20%2B%2016%5C%5C%5C%5C%28x-4%29%5E2%20%3D%2019)
The equation is now factored. To solve, take the square root of both sides and solve for x.
![\sqrt{(x-4)^2} = \sqrt{19}\\\\x-4 = \sqrt{19} \\\\x = 4 + \sqrt{19}](https://tex.z-dn.net/?f=%5Csqrt%7B%28x-4%29%5E2%7D%20%20%3D%20%5Csqrt%7B19%7D%5C%5C%5C%5Cx-4%20%3D%20%5Csqrt%7B19%7D%20%5C%5C%5C%5Cx%20%3D%204%20%2B%20%5Csqrt%7B19%7D)