At the local college, a study found that students earned an average of 14 credit hours per semester. A sample of 138 students wa
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Answer:
Step-by-step explanation:
Given the mass is m =16kg, and 1N force will stretch the spring 1 m.
That is, F =1N,Z =1m. Now find the spring constant k:
F = kL = 1 = k(1) = k= 1N/m.
The damping force is 8times the instantaneous velocity, this means β = 8,
and the external force is f(t) = 0
Initially the object compressed 0.6m above equilibrium position,
with the downward velocity is 2m/s.
The differential equation for a spring mass system with
damping force and extemal force is: mx" + βxt + kx = f(t).
so, 16x"+ 8x' + x= 0, x(0} = -0.6, x'(0)= 2m/s.
Now solve the DE:
The auxilary equation for the homogeneous equation is 16x"+8x'+x=0
solving we get, 16r² + 8r + 1 = 0 => (4r + 1)² = 0 => r = - 1/4.
Then the general solution for the homogenous system is: .
Use the initial conditions x (0) = -0.6, x'(0) = 2m/s:
.
Hence, .
The length of the rug is 4 ft.
The width of the rug is 2.5 ft.
Explanation:
The area of the rug is 10 ft.
The length of the rug be l.
Let us convert the inches to feet.
Thus,
Thus, the length of the rug is
Let the width of the rug be w.
Substituting these values in the formula of area of the rectangle, we get,
Solving the expression using the quadratic formula,
Substituting the values, we have,
Thus,
and
Since, the value of w cannot be negative, the value of w is 2.5ft
Thus, the width of the rug is 2.5ft
Substituting in
, we get,
Thus, the length of the rug is 4 ft.