Answer:
0.9 square units
Step-by-step explanation:
We assume you intend the vertices of the square to be (±√2, 0) and (0, ±√2). Then the diagonals of the square are 2√2 in length and its area is ...
(1/2)(2√2)² = 4
The radius of the inscribed circle is 1, so its area is ...
π·1² = π
and the area outside the circle, but inside the square is the difference of these areas:
area of interest = 4 - π ≈ 0.858407
area of interest ≈ 0.9
