Ask question

Ask question

All categories

3 years ago

6

Trucks in a delivery fleet travel a mean of 120 miles per day with a standard deviation of 24 miles per day. The mileage per day

is distributed normally. Find the probability that a truck drives between 108 and 153 miles in a day. Round your answer to four decimal places.

1 answer:

lora16 [44]3 years ago

7 0

Answer:

0.6069

Step-by-step explanation:

Trucks in a delivery fleet travel a mean of 120 miles per day with a standard deviation of 24 miles per day. The mileage per day is distributed normally. Find the probability that a truck drives between 108 and 153 miles in a day. Round your answer to four decimal places.

We solve using z score formula

z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

For x = 108 miles

z = ( 108 - 120)/24

z = -0.5

Probability value from Z-Table:

P(x = 108) = 0.30854

For x = 153 miles

z = (153 - 120) /24

= 1.375

Probability value from Z-Table:

P(x = 153) = 0.91543

The probability that a truck drives between 108 and 153 miles in a day is

P(x = 153) - P( x = 108)

0.91543 - 0.30854

= 0.60689

Approximately = 0.6069

You might be interested in

<img src="https://tex.z-dn.net/?f=%20%5Cunderline%7B%20%5Cunderline%7B%20%5Ctext%7Bquestion%7D%7D%7D%20%3A%20" id="TexFormula1"

Inga [223]

Answer:

$y=-\sqrt{3}x+2$

Step-by-step explanation:

We want to find the equation of a straight line that cuts off an intercept of 2 from the y-axis, and whose perpendicular distance from the origin is 1.

We will let Point M be (x, y). As we know, Point R will be (0, 2) and Point O (the origin) will be (0, 0).

First, we can use the distance formula to determine values for M. The distance formula is given by:

$\displaystyle d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Since we know that the distance between O and M is 1, d=1.

And we will let M(x, y) be (x₂, y₂) and O(0, 0) be (x₁, y₁). So:

$\displaystyle 1=\sqrt{(x-0)^2+(y-0)^2}$

Simplify:

$1=\sqrt{x^2+y^2}$

We can solve for y. Square both sides:

$1=x^2+y^2$

Rearranging gives:

$y^2=1-x^2$

Take the square root of both sides. Since M is in the first quadrant, we only need to worry about the positive case. Therefore:

$y=\sqrt{1-x^2}$

So, Point M is now given by (we substitute the above equation for y):

$M(x,\sqrt{1-x^2})$

We know that Segment OM is perpendicular to Line RM.

Therefore, their <em>slopes will be negative reciprocals</em> of each other.

So, let’s find the slope of each segment/line. We will use the slope formula given by:

$\displaystyle m=\frac{y_2-y_1}{x_2-x_1}$

Segment OM:

For OM, we have two points: O(0, 0) and M(x, √(1-x²)). So, the slope will be:

$\displaystyle m_{OM}=\frac{\sqrt{1-x^2}-0}{x-0}=\frac{\sqrt{1-x^2}}{x}$

Line RM:

For RM, we have the two points R(0, 2) and M(x, √(1-x²)). So, the slope will be:

$\displaystyle m_{RM}=\frac{\sqrt{1-x^2}-2}{x-0}=\frac{\sqrt{1-x^2}-2}{x}$

Since their slopes are negative reciprocals of each other, this means that:

$m_{OM}=-(m_{RM})^{-1}$

Substitute:

$\displaystyle \frac{\sqrt{1-x^2}}{x}=-\Big(\frac{\sqrt{1-x^2}-2}{x}\Big)^{-1}$

Now, we can solve for x. Simplify:

$\displaystyle \frac{\sqrt{1-x^2}}{x}=\frac{x}{2-\sqrt{1-x^2}}$

Cross-multiply:

$x(x)=\sqrt{1-x^2}(2-\sqrt{1-x^2})$

Distribute:

$x^2=2\sqrt{1-x^2}-(\sqrt{1-x^2})^2$

Simplify:

$x^2=2\sqrt{1-x^2}-(1-x^2)$

Distribute:

$x^2=2\sqrt{1-x^2}-1+x^2$

So:

$0=2\sqrt{1-x^2}-1$

Adding 1 and then dividing by 2 yields:

$\displaystyle \frac{1}{2}=\sqrt{1-x^2}$

Then:

$\displaystyle \frac{1}{4}=1-x^2$

Therefore, the value of x is:

$\displaystyle \begin{aligned}\frac{1}{4}-1&=-x^2\\-\frac{3}{4}&=-x^2\\ \frac{3}{4}&=x^2\\ \frac{\sqrt{3}}{2}&=x\end{aligned}$

Then, Point M will be:

$\begin{aligned} \displaystyle M(x,\sqrt{1-x^2})&=M(\frac{\sqrt{3}}{2}, \sqrt{1-\Big(\frac{\sqrt{3}}{2}\Big)^2)}\\M&=(\frac{\sqrt3}{2},\frac{1}{2})\end{aligned}$

Therefore, the slope of Line RM will be:

$\displaystyle \begin{aligned}m_{RM}&=\frac{\frac{1}{2}-2}{\frac{\sqrt{3}}{2}-0} \\ &=\frac{\frac{-3}{2}}{\frac{\sqrt{3}}{2}}\\&=-\frac{3}{\sqrt3}\\&=-\sqrt3\end{aligned}$

And since we know that R is (0, 2), R is the y-intercept of RM. Then, using the slope-intercept form:

$y=mx+b$

We can see that the equation of Line RM is:

$y=-\sqrt{3}x+2$

6 0

3 years ago

Read 2 more answers

From a train station, one train heads north, and another heads east. Some time later, the northbound train has traveled 27 kilom

galben [10]

Answer: the eastbound train had travelled 12 miles
Explanation: using Pythagoras theorem, we know that
X^2 = a^2 + b^2
Where ^ stands for raised to power.
Let
a stand for the train going towards North and
b stands for the train going towards east.
X stands for the total distance between train a and b = 20 miles.
By Pythagoras rule
X^2 = a^2 + b^2
20^2 = 16^2 + b^2
400 = 256 + b^2 so that
b^2 = 400 - 256 = 144
b = √144
b = 12 miles.

6 0

3 years ago

What is the difference?<br><br> 10.22 – 3.651

zysi [14]

Answer:

6.569

Step-by-step explanation:

Difference is subtraction.

10.22-3.651=6.569

7 0

3 years ago

Read 2 more answers

PLEASE HELP!! I’m very confuse

SVETLANKA909090 [29]

Given:

A(16, 4)

B(34, 40)

Line segment AB partition in the ratio 1 : 5.

To find:

The coordinate of a point that partitions AB.

Solution:

Section formula:

$$P(x,y)=\left(\frac{m x_{2}+n x_{1}}{m+n}, \frac{m y_{2}+m y_{1}}{m+n}\right)$

Here $x_1=16, y_1=4, x_2=34, y_2=40$ and m = 1, n = 5

$$P(x,y)=\left(\frac{1\times 34+5 \times 16}{1+5}, \frac{1\times 40+5 \times4}{1+5}\right)$

$$P(x,y)=\left(\frac{ 34+80}{6}, \frac{40+20}{6}\right)$

$$P(x,y)=\left(\frac{ 114}{6}, \frac{60}{6}\right)$

$$P(x,y)=(19, 10)$

The coordinate of point that partitions the segment AB is (19, 10).

4 0

3 years ago

Jeremiah wants to send some of his shirts to a dry cleaner. he usually takes his clothes to Spot-Less Dry cleaners, where he pay

Allisa [31]

answer:spot-less

Step-by-step explanation:

21.00 divided by 4 is 5.25 so you'd be payingmore at "no mess or stress dry"

4 0

3 years ago