Answer:
0.6069
Step-by-step explanation:
Trucks in a delivery fleet travel a mean of 120 miles per day with a standard deviation of 24 miles per day. The mileage per day is distributed normally. Find the probability that a truck drives between 108 and 153 miles in a day. Round your answer to four decimal places.
We solve using z score formula
z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.
For x = 108 miles
z = ( 108 - 120)/24
z = -0.5
Probability value from Z-Table:
P(x = 108) = 0.30854
For x = 153 miles
z = (153 - 120) /24
= 1.375
Probability value from Z-Table:
P(x = 153) = 0.91543
The probability that a truck drives between 108 and 153 miles in a day is
P(x = 153) - P( x = 108)
0.91543 - 0.30854
= 0.60689
Approximately = 0.6069
