#11
Each roll is 9' long,
length of each roll = 9' * (12"/foot) = 108"
Each ribbon piece = 15", so number of ribbons per roll
=108/15=7 with 3" left over, which is assumed not possible to be joined with other pieces.
Therefore, with 5 rolls, there are 7*5=35 pieces of ribbon, with 5 pieces or 3" left over.
P(A)=0.2
P(B)=0.3
P(A and B)= 0.2 x 0.3=0.06
Answer:
ok for this problem lets subtract 25 for 100 to get 75 so know we know we have to multiple 20 by 0.75 to get 15 dollars for the reduced price