A normal die is six sided.
The probability of rolling a 5 is 1/6
The probability of rolling a factor of 6 is 4/6 (or 2/3)
-the factors of 6 are 1, 2, 3 and 6
The probability of rolling a number more than one is 5/6
-the die is numbered 1-6, and the numbers greater than one are 2, 3, 4, 5 and 6
If you’re rolling the die 3 times and want to get those three in that specific order:
Multiply 6 x 3 to get 18
-you roll a six sided die 3 times
The probability of rolling a 5 the first time is 1/18
The probability of rolling a factor of 6 the second time is 4/18 (or 2/9)
-(see factors of 6 above)
The probability of rolling a number greater than 1 is 5/18
Next multiply 18 x 3, which is equal to 54
-this is because you want to find the EXACT theoretical probability of rolling these numbers in this exact order
Add up all your numerators
1 + 4 + 5 = 10
Your probability of rolling these numbers in this exact order is 10/54.
But you must ALWAYS simplify your fractions.
Simplify 10/54:
10 / 2 = 5
54 / 2 = 27
Your simplified fraction is 5/27.
Hope this helped! :3
(-5)+7=2
2-18= -16
-16+4= -12
-2b + 7 > 27.5
- 2b > 27.5 - 7
- 2b > 20.5
b < - 10.25
Answer:
The correct answer is D
Step-by-step explanation:
You can find the correct answer just by looking at what the first term would end up being.
The first three, if you expanded them, would all have the starting term 2x³, which does not match the result unless the two is factored out. Only the last one would end up with the correct x³ as its first term.
Let's expand it to see if we're right:
(x + 2)(x² + 3x + 5)
= x³ + 3x² + 5x + 2x² + 6x + 10
= x³ + 3x² + 11x + 10
And that's a match, so the correct answer is D