Let's split the problem in non-intersecting subsets: we have good wood racquets,
defective wood rackets,
good graphite racquets,
defective graphite rackets.
The probability that the racket is wood or defective covers the following subsets: good wood, defective wood and defective graphite, which have, respectively, ,
and
elements.
Since the total is elements, the probability is
Answer:
%82.5
Step-by-step explanation:
From point 1 we know that Moe´s grade just before taking the final exam represents 60% of the final grade. Then, using the information in the point 2 we can compute Moe´s final grade as follows:
,
where FG is Moe´s Final Grade and FE is Moe´s final exam grade. Then,
.
So, in order to receive the passing grade average of 60% for the class Moe needs to obtain in his exam:
That is, he need al least %82.5 to obtain a passing grade.