Question

(04.04 LC)

Answer 1

Answer:

The distance between T and S is 10 units.

Step-by-step explanation:

Given the points

• T(2, -4)

• S(2, 6)

$\mathrm{Compute\:the\:distance\:between\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

The distance between T and S is:

$=\sqrt{\left(2-2\right)^2+\left(6-\left(-4\right)\right)^2}$

$=\sqrt{\left(2-2\right)^2+\left(6+4\right)^2}$

$=\sqrt{0+10^2}$

$=\sqrt{10^2}$

$=10$              ∵ $\mathrm{Apply\:radical\:rule\:}\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0$

Therefore, the distance between T and S is 10 units.