Answer: (C) {x | x R, x > 3}
Explanation:
Solve the inequality for x:
x -5 > -2 | add 5
x > -2 + 5
x > 3
Solution set: all Reals x > 3, or {x | x R, x > 3}
Equation 1 for tickets sold:
$35x + $25y = $10,250
Equation 2 for quantity (number #) of tickets sold:
x + y = 350
Use substitution method:
y = 350 - x
35x + 25 (350 - x) = $10,250
35x + $8750 - 25x = $10,250
10x + $8750 = $10,250
- $8,750 -$8,750
10x = 1,500
x = 150
y = 350 - 150
y = 200
Check the answers:
$35 (150) + $25 (200) =
$5,250 + $5,000 = $10,250
I believe you meant to write
?
If that's the case I'll solve the one I provided but I'll drop the base 2 to type it faster but you need to put it always!
Remember: log a + log b = log (a*b)
So log (x+2) + log (x-2) = log [(x+2)*(x-2)] = log (x^2 - 4)
Now back to the inequality:
log (x^2 - 4) <span>≤ log 5
Raise both sides as powers of 2 ( Since it's the base of your log)
Now,
x^2 - 4 </span><span>≤ 5
Add 4 both sides:
x^2 </span>≤ 9
Square root both sides
x ≤ +3 or x ≤ -3
Reject the -3 solution as it makes both (x + 2) and (x - 2) negative and a log can never have a negative value inside its brackets.
So x <span>≤ 3 But can never be less than 2 as well for the same previous reason.
Hope that helped.</span>