I dont know exactly what it is
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Answer: Choice B</h3>
No, this is not a plausible value for the population mean, because 5 is not within the 95% confidence interval.
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Explanation:
The greek letter mu is the population mean. It has the symbol
which looks like the letter 'u' but with a tail at the front or left side.
The question is asking if mu = 5 is plausible if the researcher found the 95% confidence interval to be 5.2 < mu < 7.8
We see that 5 is <u>not</u> in that interval. It's a bit to the left of 5.2
Since mu = 5 is not in the interval, it's not a plausible value for the population mean.
Have we ruled it out with 100% confidence? No. Such a thing is not possible. There's always room for (slight) error. The researcher would need to do a census to be fully confident; however, such practices are very time consuming and expensive. This is the main reason why statistics is important to try to estimate the population with a sample.
H(x) = 6x
it gives you what x is so plug that in the equation to find it.
h(2/3) = 6(2/3)
h(2/3) = 6 × 2 ÷ 3
h(2/3) = 12 ÷ 3
h(2/3) = 4
so your answer is 4.
hope this helps, God bless!
Answer:
Sure why not.
Step-by-step explanation:
Answer:
(x - 1) (x + 1) (x - 4) (x + 4)
Step-by-step explanation:
actor the following:
x^4 - 17 x^2 + 16
x^4 - 17 x^2 + 16 = (x^2)^2 - 17 x^2 + 16:
(x^2)^2 - 17 x^2 + 16
The factors of 16 that sum to -17 are -1 and -16. So, (x^2)^2 - 17 x^2 + 16 = (x^2 - 1) (x^2 - 16):
(x^2 - 1) (x^2 - 16)
x^2 - 16 = x^2 - 4^2:
(x^2 - 1) (x^2 - 4^2)
Factor the difference of two squares. x^2 - 4^2 = (x - 4) (x + 4):
(x - 4) (x + 4) (x^2 - 1)
x^2 - 1 = x^2 - 1^2:
(x^2 - 1^2) (x - 4) (x + 4)
Factor the difference of two squares. x^2 - 1^2 = (x - 1) (x + 1):
Answer: (x - 1) (x + 1) (x - 4) (x + 4)