The given equation is 
where h is the height, in feet, of a ball and t is the time, in seconds.
<u>Part a: The height of the ball when t = 2 seconds:</u>
The height of the ball above the ground 2 seconds after it is released can be determined by substituting t= 2 in the equation , we get;
Simplifying the terms, we get;
Thus, the height of the ball after 2 seconds is 100 feet.
<u>Part b: The height of the ball when t = 4 seconds:</u>
The height of the ball above the ground 4 seconds after it is released can be determined by substituting t = 4 in the equation , we get;
Simplifying the terms, we get;
Thus, the height of the ball after 4 seconds is 68 feet.
Answer:
Step-by-step explanation:
Okay, so hopefully my crude diagram helps you visualize the problem. When in doubt, always draw a picture.
All I did was graph the points and formed a line.
Slope: It's going to be 0 because it doesn't change at all (no different y values)
(y2-y1)/(x2-x1) = (6-6) / (4-2) = 0/2 = 0
Y intercept is where the line crosses the y axis- this is also where x=0 (find it in your chart!)
Equation is y= 6; I don't know how to explain this, but trust me, it's right
A and D are correct. If u don't know why look up the definitions of the triangles
X² - 4x + 4 = 0
(x-2)(x-2) = 0
the equation has one root mainly 2 with multiplicity 2
the answer is a
