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3 years ago

HELP ME PLEASE IM BEGGING

Mathematics

2 answers:

maria [59]3 years ago

8 0

1) 8, 32
2) 6, 36
3) 5, 35

region 2 requires the most paint, as it has the highest area.

i got these answers by finding a length that would give the figure a perimeter of 24.

hope this helps!

Vesnalui [34]3 years ago

5 0

Bailey washington!2!1&1$282$/$2

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a ski chalet offers 2 weekend packages. one package provides 2 nights and 3 meals for$280. the other provides 2 nights and 5 mea

Helga [31]

1st formula 2n + 3m = 280

2nd formula 2n + 5m = 320

rearrange 1st formula to equal n:

2n = -3m + 280
 n = -3/2 m + 140

rearrange 2nd formula to equal n:

2n = -5m + 320
 n = -5/2m + 160
 so now you have

-3/2m + 140 = -5/2m + 160

Rearrange to become:
 -3/2m + 5/2m = 160 - 140
 m = 20

Now place 20 into the very 1st equation in place of the letter m
 2n + 3(20) = 280
 2n + 60 = 280
 2n = 220
 n = 110

so it costs $110 per night, $20 per meal

8 0

4 years ago

PLEASE HELP. Justice Hope's to build a fence to surround his garden. He measures and determines that he needs 24ft of fencing Wh

Assoli18 [71]

Justin’s fence will cost $72.
24ft = 24(12)
24(12) = 288 inches of fencing
288 (0.25) = $72

6 0

3 years ago

Read 2 more answers

PLEASE HELP ASAP !!!!!!!!

AnnyKZ [126]

Answer: 7°

Explanation:

FBD = EBC
2x + 3 = 9x - 11
-7x = -14
x = -14/-7
x = 2

EBC = 9(2) - 11 = 18 - 11 = 7°

7 0

3 years ago

Read 2 more answers

Solve for x. 4x - 8 = -3(2x + 6)

Alenkinab [10]

Answer:

x= -1

Step-by-step explanation:

First, distribute the -3 through the parentheses

4x-8= -3(2x+6)

= 4x-8= -6x-18

Second, move the variable to the left-hand side and change its sign

4x+6x= -18+8

10x= -10

Divide both sides by 10

x=-1

7 0

3 years ago

Read 2 more answers

Find all the solutions of the given equations in the interval [0,2pi) tan^3x=tanx and cos 3x=-cos3x

slamgirl [31]

$\tan^3x=\tan x$
$\tan^3x-\tan x=0$
$\tan x(\tan^2x-1)=0$
$\tan x(\tan x-1)(\tan x+1)=0$
$\begin{cases}\tan x=0\\\tan x-1=0\\\tan x+1=0\end{cases}$

$\tan x=\dfrac{\sin x}{\cos x}=0\implies \sin x=0\implies x=0,\pi$

$\tan x-1=0\iff\tan x=1\implies x=\dfrac\pi4,\dfrac{5\pi}4$

$\tan x+1=0\iff\tan x=-1\implies x=\dfrac{3\pi}4,\dfrac{7\pi}4$

- - -

$\cos3x=-\cos3x$
$2\cos3x=0$
$\cos3x=0\implies 3x=\dfrac\pi2,3x=\dfrac{3\pi}2\implies x=\dfrac\pi6,x=\dfrac\pi2$

This doesn't account for all the solutions, however; there are some values of $x$ that push $3x$ outside the interval $[0,2\pi)$ , so let's take a few more:

$3x=\dfrac{5\pi}2\implies x=\dfrac{5\pi}6$
$3x=\dfrac{7\pi}2\implies x=\dfrac{7\pi}6$
$3x=\dfrac{9\pi}2\implies x=\dfrac{9\pi}6$
$3x=\dfrac{11\pi}2\implies x=\dfrac{11\pi}6$

We can stop there, since the next candidate gives

$3x=\dfrac{13\pi}2\implies x=\dfrac{13\pi}6>2\pi$

7 0

3 years ago