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KIM [24]
2 years ago
13

Help me pleaseee please please please

Mathematics
2 answers:
Karo-lina-s [1.5K]2 years ago
8 0

Step-by-step explanation:

it is the second one -4(3_8×)

Gelneren [198K]2 years ago
6 0
It’s the second one. -4(3-8x)
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Need help asap!!!! will mark brainliest if correct
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The volume of a rectangular prism is length x width x height.
You will have to multiply 10.4mm by 5mm by 8mm and the product of that is 416 mm
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If p is true and q is false, the pq is Always sometimes never true.
Vinvika [58]
Answer:
pq is never true
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3 years ago
$300 at 6% for 3 years
Charra [1.4K]
Its I=prt 
so plug it in
I=300(.06)3 i got .06 because you have 6% you have to move the decimal  the left twice 0.06 is what you get
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7 0
3 years ago
What are the first five common multiples of 4 and 7
denis23 [38]
Easy, just write out the multiple of the numbers.

4: 4,8,12,16,20,24,28,32,36,40,44,48,52,56,60

7: 7,14,21,28,35,42,49,56,63,70 

Etc.

But a few common multiples:

28,56,84,112,140

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6 0
3 years ago
Consider the function f ( x ) = − 2 x 3 + 27 x 2 − 108 x + 9 . For this function there are three important open intervals: ( − [
Darya [45]

Answer:

<em>A=3 and B=6</em>

Step-by-step explanation:

<u>Increasing and Decreasing Intervals of Functions</u>

Given f(x) as a real function and f'(x) its first derivative.

If f'(a)>0 the function is increasing in x=a

If f'(a)<0 the function is decreasing in x=a

If f'(a)=0 the function has a critical point in x=a

As we can see, the critical points may define open intervals where the function has different behaviors.

We have

f ( x ) = - 2 x^3 + 27 x^2 - 108 x + 9

Computing the first derivative:

f' ( x ) = - 6 x^3 + 54 x - 108

We find the critical points equating f'(x) to zero

- 6 x^3 + 54 x - 108=0

Simplifying by -6

x^2 -9 x +18=0

We get the critical points

x=3,\ x=6

They define the following intervals

(-\infty,3),\ (3,6),\ (6,+\infty)

Thus A=3 and B=6

3 0
3 years ago
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