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almond37 [142]
3 years ago
10

How would you solve x^3=8

Mathematics
1 answer:
kozerog [31]3 years ago
8 0

Answer:

2

Step-by-step explanation:

x^{3} =8\\x=\sqrt[3]{8} \\x=2

use your calculator

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Find the value of c so that (x+2) is a factor of the polynomial p(x). p(x)=4x^3+cx^2+x+2
Wittaler [7]

Answer:

c = 8

Step-by-step explanation:

Use synthetic division here; it's the fastest approach.

Given that (x + 2) is a factor, take -2 and use this as the divisor in synthetic division:

-2     4         c                1           2

                  -8    (-2c+ 16)      (4c-34)

       ---------------------------------------------

         4    (c - 8)   (-2c + 17)     4c - 32

The remainder, 4c - 32, must equal zero if (x + 2) is a factor.

Then 4c - 32 = 0, and c = 8

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3 years ago
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Step-by-step explanation:

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8 0
3 years ago
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laila [671]

It's a quadratic equation in disguise. If you let y=x^{-1}, then y^2=x^{-2}, and we can rewrite the equation as

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But we want to solve for x, so we have

y=x^{-1}=\dfrac25\implies x=\dfrac52

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2 years ago
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