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almond37 [142]
3 years ago
10

How would you solve x^3=8

Mathematics
1 answer:
kozerog [31]3 years ago
8 0

Answer:

2

Step-by-step explanation:

x^{3} =8\\x=\sqrt[3]{8} \\x=2

use your calculator

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12. Find the distance between points P(-1, 2) and Q(-3, 4).​
marusya05 [52]

Answer:

D=2.82

Step-by-step explanation:

Here we are given with two coordinates and asked to determine the distance between them.

Here we are going to use the distance formula, which is given as under

D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}

Where

(x_1,y_1) = (-1,2)

(x_2,y_2) = (-3,4)

Replacing these values in the distance formula

D =\sqrt{(-1-(-3))^2+(2-4)^2}

D =\sqrt{(-1+3)^2+(-2)^2}

D =\sqrt{(2)^2+4}

D =\sqrt{4+4}

D =\sqrt{8}

D= 2.8284

Hence the Distance is 2.82 units

3 0
3 years ago
Kate has 25 skirts, out of which 10 are white. if Kate randomly selects a skirt to wear, what is the probability it will be whit
ivanzaharov [21]

Answer:

10/25 or in percentage it is 40%

Step-by-step explanation:

3 0
3 years ago
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Use substitution to solve the system.<br> x=3y+5<br> 5x-4y=14<br> ______________<br> x=<br> y=
nataly862011 [7]
So what you do is go 5(3y+5)-4y=14 which equals 15y+25-4y=14 which turns into 11y+25=14 than you move the 25 over which equals 11y=-11 so y=-1 then you enter -1 in for y which looks like 5x-4(-1)=14 than you solve that which is 5x+4=14 than you move the 4 over and you get 5x=10 than x=2

x=2
y=-1
8 0
3 years ago
PLEASE HELP!!! BRAINLIEST TO CORRECT COMPLETE ANSWER!
notka56 [123]

Answer:

y=16x+1

Step-by-step explanation:

You want to find the equation for a line that passes through the two points:

(1,17) and (2,33).

First of all, remember what the equation of a line is:

y = mx+b

Where:

m is the slope, and

b is the y-intercept

First, let's find what m is, the slope of the line...

The slope of a line is a measure of how fast the line "goes up" or "goes down". A large slope means the line goes up or down really fast (a very steep line). Small slopes means the line isn't very steep. A slope of zero means the line has no steepness at all; it is perfectly horizontal.

For lines like these, the slope is always defined as "the change in y over the change in x" or, in equation form:

So what we need now are the two points you gave that the line passes through. Let's call the first point you gave, (1,17), point #1, so the x and y numbers given will be called x1 and y1. Or, x1=1 and y1=17.

Also, let's call the second point you gave, (2,33), point #2, so the x and y numbers here will be called x2 and y2. Or, x2=2 and y2=33.

Now, just plug the numbers into the formula for m above, like this:

m=  

33 - 17/  2 - 1

or...

m=  16/ 1

or...

m=16

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

y=16x+b

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

(1,17). When x of the line is 1, y of the line must be 17.

(2,33). When x of the line is 2, y of the line must be 33.

Because you said the line passes through each one of these two points, right?

Now, look at our line's equation so far: y=16x+b. b is what we want, the 16 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (1,17) and (2,33).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!.

You can use either (x,y) point you want..the answer will be the same:

(1,17). y=mx+b or 17=16 × 1+b, or solving for b: b=17-(16)(1). b=1.

(2,33). y=mx+b or 33=16 × 2+b, or solving for b: b=33-(16)(2). b=1.

See! In both cases we got the same value for b. And this completes our problem.

The equation of the line that passes through the points

(1,17) and (2,33)  is   y=16x+1

4 0
3 years ago
What is equal to 2/4
Travka [436]
Fractions: 4/8, 1/2

Percent: 50%

Decimal: 0.50
8 0
3 years ago
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