Find the coordinates of a point that is in Quadrant IV and is √45 units away from the point (-4, 1).
1 answer:
Answer:
15-3
Step-by-step explanation:
15x3=45 or it could be 3-15
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Answer: n=0.4 or 2/5
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Answer:
acute isosceles
Step-by-step explanation:
You just have to divide the 1/2 a pound by 8, or equivalently multiply by (1/8):
(1/2)*(1/8) = 1/16 of a pound
