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ahrayia [7]
3 years ago
15

Points C and D divide the semicircle into three equal parts. Match the angles with their measures.

Mathematics
2 answers:
Tresset [83]3 years ago
7 0
∠CAE = 120°
∠CAD = 60°
∠BAE = 180°
∠DEC = 30°

We start out with the fact that points C and D split the semicircle into 3 sections.  This means that ∠BAC, ∠CAD and ∠DAE are all 60° (180/3 = 60).

Since it forms a straight line, ∠BAE is 180°.

Since it is formed by ∠CAD and ∠DAE, ∠CAE = 60+60 = 120°.

We know that an inscribed angle is 1/2 of the corresponding arc; since CD is 1/3 of the circle, it is 1/3(180) = 60; and this means that ∠DEC = 30°.
USPshnik [31]3 years ago
6 0

If this person is correct then it should look like this if you have Plato

your welcome ;0 =)

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\hbox{Domain:}\\
x^2+x-2\geq0 \wedge x^2-4x+3\geq0 \wedge x^2-1\geq0\\
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x\in(-\infty,-2\rangle\cup\langle1,\infty) \wedge x\in(-\infty,1\rangle \cup\langle3,\infty) \wedge x\in(-\infty,-1\rangle\cup\langle1,\infty)\\
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\sqrt{x^2+x-2}+\sqrt{x^2-4x+3}=\sqrt{x^2-1}\\
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2\sqrt{(x^2+x-2)(x^2-4x+3)}=-x^2+3x-2\\
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There's one more condition I forgot about
-(x-2)(x-1)\geq0\\
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