Larry rolls 2 fair dice and adds the results from each.
1 answer:
Answer:
Step-by-step explanation:
The samples are
{ ( 1 , 1) , ( 1 , 2 ) , ( 1 , 3 ) , ( 1 , 4 ) , ( 1 , 5) , ( 1 , 6 )
( 2 , 1 ) , ( 2 2 ) , ( 2 , 3 ) , ( 2 , 4 ) , ( 2 , 5 ) , ( 2 , 6 )
( 3 , 1 ) , ( 3 , 2 ) , ( 3 , 3 ) , ( 3 , 4 ) , ( 3 , 5 ) , ( 3 , 6 )
( 4 , 1 ) , ( 4 , 2 ) , ( 4 , 3 ) , ( 4 , 4 ) , ( 4 , 5 ) , ( 4 , 6 )
( 5 , 1 ) , ( 5 , 2 ) , ( 5 , 3 ) , ( 5 , 4 ) , ( 5 , 5 ) , ( 5 , 6 )
( 6 , 1 ) , ( 6 , 2 ) , ( 6 , 3 ) , ( 6 , 4 ) , ( 6 , 5 ) , ( 6 , 6 ) }
Total number of samples = 36
Samples with a sum of 8 = { ( 2 , 6 ) , ( 3 , 5 ) , ( 4 , 4 ) , ( 5 , 3 ) , ( 6 , 2 ) }
Total number of sample with sum 8 = 5
Therefore,
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The value of line integral is, 73038 if the c is the given curve. C xeyz ds, c is the line segment from (0, 0, 0) to (2, 3, 4)
<h3>What is integration?</h3>It is defined as the mathematical calculation by which we can sum up all the smaller parts into a unit.
The parametric equations for the line segment from (0, 0, 0) to (2, 3, 4)
x(t) = (1-t)0 + t×2 = 2t
y(t) = (1-t)0 + t×3 = 3t
z(t) = (1-t)0 + t×4 = 4t
Finding its derivative;
x'(t) = 2
y'(t) = 3
z'(t) = 4
The line integral is given by:
After solving the integration over the limit 0 to 1, we will get;
or
= 73037.99 ≈ 73038
Thus, the value of line integral is, 73038 if the c is the given curve. C xeyz ds, c is the line segment from (0, 0, 0) to (2, 3, 4)
Learn more about integration here:
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