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AlladinOne [14]
2 years ago
14

Michelle has a bag with marbles in it. Some of the marbles are blue, some are green, and some are yellow. She draws one marble a

t random, records the color, and returns it to the bag.
Here is her data after 500 trials:
blue: 120
green:119
yellow:261

She wants to know the probability of drawing a blue marble from the bag. Which of these probabilities is most likely?
Mathematics
1 answer:
sammy [17]2 years ago
3 0

Answer:

24% (0.24)

Step-by-step explanation:

Using the data from her 500 trials, we can predict the probability of her drawing a blue marble from the bag by dividing the number of times she drew a blue marble (120) by the total of trials she performed (500).

120 ÷ 500 = 0.24

0.24 = 24%

~Hope this helps!~

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Answer:

Part A) The length of a straight line between the school and the Fire Station is 4.6\ miles

Part B) The length of a straight line between the school and the hospital is 2.1\ miles

Step-by-step explanation:

<u><em>The complete question in the attached figure</em></u>

Let

The positive x-coordinates ----> East

The positive y-coordinates ----> North

The negative x-coordinates ----> West

The negative y-coordinates ----> South

take the point A (0,0) as the Middle School (reference point)

Part A) we have

Town Hall is located 4.3 miles directly east of the Middle School

so

The coordinates of Town Hall are B(4.3,0)

The Fire Station is located 1.7 miles directly North of Town Hall

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The coordinates of Fire Station are C(4.3,1.7)

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Remember that

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

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A(0,0) and C(4.3,1.7)

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d=\sqrt{(1.7-0)^{2}+(4.3-0)^{2}}

d=\sqrt{(1.7)^{2}+(4.3)^{2}}

d=4.6\ miles

Part B) we have that

The hospital is 3.1 miles west of the fire station

so

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D(1.2,1.7)

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Remember that

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d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have

A(0,0) and D(1.2,1.7)

substitute

d=\sqrt{(1.7-0)^{2}+(1.2-0)^{2}}

d=\sqrt{(1.7)^{2}+(1.2)^{2}}

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