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AlladinOne [14]
3 years ago
14

Michelle has a bag with marbles in it. Some of the marbles are blue, some are green, and some are yellow. She draws one marble a

t random, records the color, and returns it to the bag.
Here is her data after 500 trials:
blue: 120
green:119
yellow:261

She wants to know the probability of drawing a blue marble from the bag. Which of these probabilities is most likely?
Mathematics
1 answer:
sammy [17]3 years ago
3 0

Answer:

24% (0.24)

Step-by-step explanation:

Using the data from her 500 trials, we can predict the probability of her drawing a blue marble from the bag by dividing the number of times she drew a blue marble (120) by the total of trials she performed (500).

120 ÷ 500 = 0.24

0.24 = 24%

~Hope this helps!~

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Three fourths a number plus 8 is 20 less than the number
VARVARA [1.3K]

Answer:

Equation:  \frac{3}{4}n+8=n-20

Solve for n:  n = 112

Step-by-step explanation:

To first set up the equation, you need to look at the verbal description and translate into numbers and operations:

'three fourths a number' =  \frac{3}{4} n

'plus 8' = + 8

'is' =

'20 less' = - 20

'the number' = n

Put the expressions together:

'three fourths a number plus 8':  \frac{3}{4}n+8

'20 less than the number': n - 20

Set them equal to each other and solve: \frac{3}{4}n+8=n-20

Add 20 to both sides: \frac{3}{4}n+8+20=n-20+20

Subtract \frac{3}{4}n from both sides: \frac{3}{4}n-\frac{3}{4}n+28=n-\frac{3}{4}n

Multiply both sides by \frac{4}{1}: \frac{4}{1}28=\frac{1}{4}n\frac{4}{1}

Solve for n:  n = 112

7 0
3 years ago
Compare square root of one hundred eighty and one hundred two eighths using <, >, or =.
olga2289 [7]

Converting the mixed number to a decimal, the correct comparison of the numbers is given as follows:

\sqrt{180} > \sqrt{100 \frac{2}{8}}

<h3>What is a mixed number?</h3>

A mixed number is represented by an integer part and a fractional part, as follows:

a b/c.

In which:

  • a is the integer part.
  • b/c is the fractional part.

In this problem, the numbers are given as follows:

\sqrt{180}, \sqrt{100 \frac{2}{8}}

The mixed number is:

100 and 2/8 = 100 + 0.25 = 100.25.

The square root is an increasing function, hence the higher the input, the higher the square root, as 180 > 100 the comparison is:

\sqrt{180} > \sqrt{100 \frac{2}{8}}

More can be learned about mixed numbers at brainly.com/question/1746829

#SPJ1

6 0
2 years ago
Write an equation in slope-Intercept form for the line with slope 2/5 and y- ntercept - 3 .
Trava [24]

Answer:

y = \frac{2}{5} x - 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = \frac{2}{5} and c = - 3 , then

y = \frac{2}{5} x - 3 ← equation of line

7 0
3 years ago
Read 2 more answers
Allan borrows 1870 dollars from his uncle. Two years later, he borrows another 1240 dollars. If his uncle charges him 8 percent
Anna11 [10]
For t=0
<span>Allan borrows--------------------------- > 1870 dollars

for t=6 years
</span>F1 = P*(1 +(r/m))^n
i=r/m
n=m*t---------- >1*6=6
we have
P1=1870
r=8%
m=1
t=6 years
F1 = 1870*(1 +(0.08/1))^6------------------ >2967.45 dollars

for t=2
Allan borrows--------------------------- > 1240 dollars

for t=6 years
F2 = P2*(1 +(r/m))^n
i=r/m
n=m*t---------- >1*4=4
we have
P2=1240
r=8%
m=1
t=4 years------------> (6-2)=4 years
F2 = 1240*(1 +(0.08/1))^4------------------ >1687 dollars

F1+F2=2967.45+1687=4654.45 dollars
the answer is 4654.45 dollars


3 0
3 years ago
A circle whose center is the origin passes through the point (-5,12). Which point also lies on this circle?
schepotkina [342]
The answer is B(11, 2sqrt(12) )
proof

the main equation of the circle is   (x-x1)²+(y-y1)²=R²
where C(x1, y1) is the center 
so if the center is the origin, it is O(0,0), and the equation becomes
<span>  (x)²+(y)²=R²
</span>and the circle passes through the point (-5,2) so we can write 
(-5)²+12²=R², it implies R= sqrt(25+144)=sqrt(169)=13

and  for <span>B(11, 2sqrt(12) )     </span>11²+  (2sqrt(12))²= 121 + 48= 169= 13
it is checked.
3 0
3 years ago
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