For domain 2x sqrt(2+x)>0
x>0,2+x>0,x>-2 combining
we get x>2
f'(x)=[1/{2x sqrt(2+x)}][{2x/(2 sqrt(2+x))}+2 sqrt(2+x)]
Answer:
Gretchen has mostly more than Manuel.
Step-by-step explanation:
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It is y=x-150 because x−150+150=y+150
Answer:
If the number you are rounding is followed by 5, 6, 7, 8, or 9, round the number up. If the number you are rounding is followed by 0, 1, 2, 3, or 4, round the number down.
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Answer:
The third one
Step-by-step explanation:
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