Answer:
Never
Never
Never
Step-by-step explanation:
The equations given are
2x1−6x2−4x3 = 6 ....... (1)
−x1+ax2+4x3 = −1 ........(2)
2x1−5x2−2x3 = 9 ..........(3)
the values of a for which the system of linear equations has no solutions
Let first add equation 1 and 2. Also equation 2 and 3. This will result to
X1 + (a X2 - 6X2) - 0 = 5
And
X1 + (aX2-5X2) + 2X3 = 8
Since X2 and X3 can't be cancelled out, we conclude that the value of a is never.
a unique solution,
Let first add equation 1 and 2. Also equation 2 and 3. This will result to
X1 + (a X2 - 6X2) - 0 = 5
And
X1 + (aX2-5X2) + 2X3 = 8
The value of a = never
infinitely many solutions.
Divide equation 1 by 2 we will get
X1 - 3X2 - 2X3 =3
Add the above equation with equation 3. This will result to
3X1 - 8X2 - 4X3 = 12
Everything ought to be the same. Since they're not.
Value of a = never.
Answer:
2 hours, 9 minutes (and 19 seconds if u wanna be exact)
Step-by-step explanation:
The square root of 25/64=5/8
Answer:
a) x² +1
b) x² +25
Step-by-step explanation:
a) (x+i)(x− i)
= x² - ( i ) x + ( i ) x - ( i)²
= x² - i² ∵ i² = -1
= x² - (-1)
= x² +1
b) (x+5 i)(x− 5i)
= x² - ( 5 i ) x + ( 5 i ) x - ( 5 i)²
= x² - 25 i² ∵ i² = -1
= x² - 25(-1)
= x² +25
we can also solve
using identity
(a + b)(a - b) = a² - b²
= (x+5 i)(x− 5i)
= x² - (5 i)²
= x² - 25 i²
= x² +25
