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mariarad [96]
2 years ago
5

What is y<-1/2x+1 and y≤x-2??

Mathematics
1 answer:
natka813 [3]2 years ago
3 0
This is your perfect answer

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How to rank linear functions
Maurinko [17]

In linear algebra, the rank of a matrix

A

A is the dimension of the vector space generated (or spanned) by its columns.[1] This corresponds to the maximal number of linearly independent columns of

A

A. This, in turn, is identical to the dimension of the vector space spanned by its rows.[2] Rank is thus a measure of the "nondegenerateness" of the system of linear equations and linear transformation encoded by

A

A. There are multiple equivalent definitions of rank. A matrix's rank is one of its most fundamental characteristics.

The rank is commonly denoted by

rank

⁡

(

A

)

{\displaystyle \operatorname {rank} (A)} or

rk

⁡

(

A

)

{\displaystyle \operatorname {rk} (A)}; sometimes the parentheses are not written, as in

rank

⁡

A

{\displaystyle \operatorname {rank} A}.

4 0
3 years ago
I need this one, answer please?
Stolb23 [73]

Answer:

Pair 1.

Step-by-step explanation:

On pair 1, shape A can go into shape B with a rotation.

Pair 2 would be a translation.

Pair 3 would be a reflection across the x-axis.

Pair 4 would be a reflection across the y-axis.

6 0
3 years ago
Read 2 more answers
The absolute values of two numbers that are additive inverses will ____________ be the same.
zhannawk [14.2K]

Answer:

A number and its additive inverse are always the same distance from zero, and so they have the same absolute value.

Step-by-step explanation:

Hope this helps!!

7 0
3 years ago
Read 2 more answers
Find lim ?x approaches 0 f(x+?x)-f(x)/?x where f(x) = 4x-3
Whitepunk [10]

If f(x)=4x-3:

\displaystyle\lim_{\Delta x\to0}\frac{(4(x+\Delta x)-3)-(4x-3)}{\Delta x}=\lim_{\Delta x\to0}\frac{4\Delta x}{\Delta x}=4

If f(x)=4x^{-3}:

\displaystyle\lim_{\Delta x\to0}\frac{\frac4{(x+\Delta x)^3}-\frac4{x^3}}{\Delta x}=\lim_{\Delta x\to0}\frac{\frac{4x^3-4(x+\Delta x)^3}{x^3(x+\Delta x)^3}}{\Delta x}

\displaystyle=\lim_{\Delta x\to0}\frac{4x^3-4(x^3+3x^2\Delta x+3x(\Delta x)^2+(\Delta x)^3)}{x^3\Delta x(x+\Delta x)^3}

\displaystyle=\lim_{\Delta x\to0}\frac{-12x^2\Delta x-12x(\Delta x)^2-4(\Delta x)^3}{x^3\Delta x(x+\Delta x)^3}=-\frac{12}{x^4}

7 0
3 years ago
The system of equations Y =-3x+2 and Y = 3x-6 is shown on the graph below.
Ira Lisetskai [31]

Answer:

A

Step-by-step explanation:

8 0
3 years ago
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