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mariarad [96]
2 years ago
5

What is y<-1/2x+1 and y≤x-2??

Mathematics
1 answer:
natka813 [3]2 years ago
3 0
This is your perfect answer

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Which of the following is equivalent to f(x)?
Fynjy0 [20]

Answer:

  • D. x^{-3/2}

Step-by-step explanation:

<u>Given function:</u>

  • f(x) = \frac{1}{x\sqrt{x} }

<u>Equivalent expression is:</u>

  • \frac{1}{x\sqrt{x} } = x^{-1}x^{-1/2} = x^{-1 - 1/2} = x^{-3/2}

Correct choice is D

6 0
2 years ago
Find w.<br><br> A. 8.9<br><br> B. 0.05<br><br> C. 0.08<br><br> D. 5.2
enyata [817]

Answer:

Step-by-step explanation:

Measure of angle V = 180 - 62 - 36 = 82 degrees

So by the law of sines, 10/sin(82 deg) = w/sin(62 deg)

w = [10sin(62)]/sin(82)

from here just plug this into a calculator

4 0
2 years ago
How do you solve what is 30% of $240
DerKrebs [107]
The Answer would be x=72. Why? Because \frac{x}{240} =  \frac{30}{100}.   Fraction  \frac{30}{100} is your %.  You Cross multiply 240 * 30 = 100x
240 time 30 = 7200. you want x to  be alone so you do 7200 divided by 100 equaling 72. So you get x=72. 
6 0
3 years ago
Which is the simplified form of the expression?
Anon25 [30]

Given:

Consider the given expression is:

10n-\dfrac{1}{3}(9n-12)

To find:

The simplified form of the given expression.

Solution:

We have,

10n-\dfrac{1}{3}(9n-12)

Using distributive property, it can be written as:

=10n-\dfrac{1}{3}(9n)-\dfrac{1}{3}(-12)

=10n-3n+4

=7n+4

Therefore, the correct option is A.

4 0
3 years ago
1) If the alpha level is changed from α = .05 to α = .01, what happens to boundaries for the critical region?
Alexxandr [17]

Answer:

1) a. Move farther into the tails

2) a. Decreases

Step-by-step explanation:

Hello!

1)

Let's say for example that you are making a confidence interval for the mean, using the Z-distribution:

X[bar] ± Z_{1-\alpha /2} * \frac{Sigma}{\sqrt{n} }

Leaving all other terms constant, this are the Z-values for three different confidence levels:

90% Z_{0.95}= 1.648

95% Z_{0.975}= 1.965

99% Z_{0.995}= 2.586

Semiamplitude of the interval is

d= Z_{1-\alpha /2} * \frac{Sigma}{\sqrt{n} }

Then if you increase the confidence level, the value of Z increases and so does the semiamplitude and amplitude of the interval:

↑d= ↑Z_{1-\alpha /2} * \frac{Sigma}{\sqrt{n} }

They have a direct relationship.

So if you change α: 0.05 to α: 0.01, then the confidence level 1-α increases from 0.95 to 0.99, and the boundaries move farther into the tails.

2)

The significance level of a hypothesis test is the probability of committing a Type I error.

If you decrease the level from 5% to 1%, then logically, the probability decreases.

I hope this helps!

5 0
3 years ago
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