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larisa [96]
3 years ago
13

Eric's father Works two part-time jobs one in the morning and one in the afternoon and works a total of 40 hours each five day w

orkweek if your schedule is the same each day and he works 3 hours each morning how many hours does Eric's father work each afternoon
Mathematics
2 answers:
suter [353]3 years ago
7 0
3 * 5 = 15 that is how many hours he works in the mornings

40 - 15 = 25

He works 25 hours in the afternoon every week.
25 / 5 = 5

So his father works 5 hours every after noon 5 days out of the week
Andrew [12]3 years ago
3 0

Answer:

8

Step-by-step explanation:

because 40 devided by 5 equals 8 so thats how many hours in the afternoon

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According to the secant-tangent theorem, we have the following expression:

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Then, we use the quadratic formula:

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Where a = 1, b = 6, and c = -315.

\begin{gathered} x_{1,2}=\frac{-6\pm\sqrt[]{6^2-4\cdot1\cdot(-315)}}{2\cdot1} \\ x_{1,2}=\frac{-6\pm\sqrt[]{36+1260}}{2}=\frac{-6\pm\sqrt[]{1296}}{2} \\ x_{1,2}=\frac{-6\pm36}{2} \\ x_1=\frac{-6+36}{2}=\frac{30}{2}=15 \\ x_2=\frac{-6-36}{2}=\frac{-42}{2}=-21 \end{gathered}<h2>Hence, the answer is 15 because lengths can't be negative.</h2>
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you should have $16 and a coupon for a $5 discount at a local supermarket. a bottle of olive oil costs$7. how many bottles of ol
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We want to find f such that \nabla f=\vec F. This means

\dfrac{\partial f}{\partial x}=-6x+5y\implies f(x,y)=-3x^2+5xy+g(y)

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so \vec F is conservative.

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\mathrm{curl}\vec F=\left(\dfrac{\partial(-2y)}{\partial z}-\dfrac{\partial(1)}{\partial y}\right)\vec\imath+\left(\dfrac{\partial(-3x)}{\partial z}-\dfrac{\partial(1)}{\partial z}\right)\vec\jmath+\left(\dfrac{\partial(-2y)}{\partial x}-\dfrac{\partial(-3x)}{\partial y}\right)\vec k=\vec0

Then

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\dfrac{\partial f}{\partial z}=1=\dfrac{\mathrm dh}{\mathrm dz}\implies h(z)=z+C

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so \vec F is conservative.

4 0
3 years ago
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forsale [732]

Answer:

<h2>The answer is .... <u><em> x = 3/2</em></u><em> </em>and if you want to write it as a mixed fraction i will be x= <u><em>1 and 1/2</em></u></h2>

Step-by-step explanation:

Hope this Helped :)

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3 years ago
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