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2 years ago

If arc AD = 62° and arc BC = 28°, then what is the measure of angle AED?

Mathematics

1 answer:

nata0808 [166]2 years ago

6 0

Well according to the Inscribed Angle Theorem, the angle inscribed in a circle is equal to one-half of its intercepted arc. We can apply that theorem to this problem as well. So the measure of AED = 1/2( arc AD + arc BC). Plug in the numbers and simplify.
AED = 1/2( 62 + 28)
AED = 1/2( 90 )
AED = 45
So the measure of angle AED is B. 45 degrees.
Hope I helped!

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Answer:

4 months

Step-by-step explanation:

Franco's provider = 60 + 42.95x

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2 years ago

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elena-s [515]

Answer:

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Step-by-step explanation:

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2 years ago

PLEASE HELP! WILL MARK BRAINLIEST

Veseljchak [2.6K]

The value of x is 3, while the length of the rectangle is 30 units and the width is 24 units.

<h3>How to determine the dimensions?</h3>

The given parameters are:

Base = 5(x+3)

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The perimeter of a rectangle is

P = 2 *(Base + Height)

So, we have:

2 *(5(x + 3) + 2(x + 9)) = 108

Divide both sides by 2

5(x + 3) + 2(x + 9) = 54

Open the brackets

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Substitute x = 3 in Base = 5(x+3) and Height = 2(x+9)

Base = 5(3+3) = 30

Height = 2(3+9) = 24

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brainly.com/question/24571594

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1 year ago

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Murljashka [212]

Answer:

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Step-by-step explanation:

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