Well according to the Inscribed Angle Theorem, the angle inscribed in a circle is equal to one-half of its intercepted arc. We can apply that theorem to this problem as well. So the measure of AED = 1/2( arc AD + arc BC). Plug in the numbers and simplify. AED = 1/2( 62 + 28) AED = 1/2( 90 ) AED = 45 So the measure of angle AED is B. 45 degrees. Hope I helped!
